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4 years ago

What are some tasks commonly performed in Power, Structural, and Technical Systems jobs? Check all that apply.

Physics

2 answers:

devlian [24]4 years ago

8 0

Answer: operating large equipment, testing and fixing machinery, recording information, tracking supplies

Explanation:

DanielleElmas [232]4 years ago

5 0

Answer:

Answer: operating large equipment, testing and fixing machinery, recording information, tracking supplies

Explanation:

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El peso de un cuerpo es de 392.2 N ¿Cuál es su masa?

alexandr1967 [171]

Answer:

⇒ To find the mass, we apply the following formula:

$\boxed{ \boxed{\mathbf{m=\dfrac{w}{g} }}}$

Data:

➢ $\textrm{Weight(w) = 392.2 Newtons}$

➢ $\mathrm{Gravity(g) = \ 9,81\ m/s^{2} }$

➢ $\textrm{Mass(m) =\ ?}$

∴ We replace and develop:

$\mathrm{m=\dfrac{w}{g} }$

$\mathrm{Mass=\dfrac{392.2}{9.81} }$

$\mathrm{Mass =39.9\ kg }$

3 0

3 years ago

John is going to use a rope to pull his sister Laura across the ground in a sled through the snow. He is pulling horizontally wi

bulgar [2K]

Answer:

The mass of Laura and the sled combined is 887.5 kg

Explanation:

The total force due to weight of Laura and friction on the sled can be calculated as follows;

$F_T = F_L+F_S$

= (400 + 310) N

= 710 N

From Newton's second law of motion, "the rate of change of momentum is directly proportional to the applied force.

$F_T = \frac{(M_L+M_S)V}{t}$

where;

$M_L$ is mass of Laura and

$M_S$ is mass of sled

Mass of Laura and the sled combined is calculated as follows;

$(M_L+M_S) = \frac{F_T*t}{V}$

given

V = Δv = 4-0 = 4m/s

t = 5 s

$(M_L+M_S) = \frac{710*5}{4}\\\\(M_L+M_S) = 887.5 kg$

Therefore, the mass of Laura and the sled combined is 887.5 kg

4 0

3 years ago

PLEASE HELP!!!!! Will give brainliest to best answer

PolarNik [594]

Answer:

the answer is d

Explanation:

I took the test

6 0

4 years ago

Calculate the GPE of a rock with a mass of 55kg on a cliff that is 27m high

GaryK [48]

Answer:

P=mgh

P=mghm=55

P=mghm=55g=9.8 or ~10

P=mghm=55g=9.8 or ~10h=27

Explanation:

hope it will help you have a great day bye and Mark brainlist if the answer is correct

 $kai6417$ 

 #carry on learning

4 0

2 years ago

Electrons in a particle beam each have a kinetic energy of 4.0 × 10−17 J. What is the magnitude of the electric field that will

denpristay [2]

Explanation:

Relation between work and change in kinetic energy is as follows.

$W_{net} = \Delta K$

Also, $\Delta K = K_{initial} - K_{final}$

= $(0 - 4.0 \times 10^{-17})$ J

= $-4.0 \times 10^{-17}$ J

Let us assume that electric force on the electron has a magnitude F. The electron moves at a distance of 0.3 m opposite to the direction of the force so that work done is as follows.

w = -Fd

$-4.0 \times 10^{-17} J = -F \times 0.3 m$

F = $1.33 \times 10^{-16}$

Therefore, relation between electric field and force is as follows.

E = $\frac{F}{q}$

= $\frac{1.33 \times 10^{-16}}{1.60 \times 10^{-19} C}$

= $0.831 \times 10^{3}$ C

Thus, we can conclude that magnitude of the electric field that will stop these electrons in a distance of 0.3 m is $0.831 \times 10^{3}$ C.

3 0

4 years ago