The coefficient of friction is 0.5.
<h3>What is Coefficient of friction?</h3>
The ratio of friction force to normal force is known as the coefficient of friction (COF), which has no dimensions. Those materials are said to as lubricous if their COF is less than 0.1. Surface roughness and COF are dependent on the composition of the materials.
Initial velocity, u=30m/s
time taken = 6s
Final velocity, v=0
Acceleration of friction, a=μg=10μms⁻²
Apply first kinematic equation of motion,
v - u = at
0 - 30 = (-10μms⁻²) × 6
-30 = -60μ
μ = 1/2
μ = 0..5
Hence, coefficient of friction is 0.5
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Continental drifts i'm pretty sure
True, physical excercise helps
Answer:
(a). The rotational inertia is 
(b). The magnitude of the magnetic torque is 
Explanation:
Given that,
Mass of neutron 
Density of neutron 
(a). We need to calculate the rotational inertia
Using formula of rotational inertia for sphere
...(I)
We know that,

Put the value of volume


Put the value of R in equation (I)

Put the value into the formula


The rotational inertia is
.
(b). We need to calculate the magnitude of the magnetic torque
Using formula of torque

Put the value into the formula


The magnitude of the magnetic torque is 
Hence, (a). The rotational inertia is 
(b). The magnitude of the magnetic torque is 
Planet Y has rotated by 135.5° through during this time.
To find the answer, we need to know about the relation between angle and radius of orbit.
<h3>What's the expression of angle in terms of radius?</h3>
- Angle= arc/radius
- As arc = orbital velocity × time,
angle= (orbital velocity × time)/radius
- Orbital velocity= √(GM/radius), G= gravitational constant and M = mass of sun
- So, angle = (√(GM)× time)/radius^3/2
<h3>What's is the angle rotated by planet Y after 5 years, if ratio of the radius of orbit of planet X and Y is 4:3 and planet X is rotated by 88°?</h3>
- Let Ф₁= angle rotated by planet Y, Ф₂= angle rotated by planet X
- As time = 5 years ( a constant)
- Ф₁/Ф₂= (radius of planet X / radius of planet Y)^(3/2)
- Ф₁= (radius of planet X / radius of planet Y)^(3/2) × Ф₂
= (4/3)^(3/2) × 88°
= 135.5°
Thus, we can conclude that Planet Y has rotated by 135.5° through during this time.
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