Remmber pemdas or gemdas or bodmas or whatever
exponential laws
(x^m)^n=x^(mn)
ok so
(3^2)(2a)^(3/2))^2=
(3^2)(2a)^((3/2)*2)=
(3^2)(2a))^(6/2)=
(3^2)(2a)^3=
(3^2)(8a^3)^3=
(9)(8a^3)=
72a^3
2nd one from left
b. 9.2
Step-by-step explanation:
cos(52) × 15 gives you the adjacent which is 9.2
1 and 1/2 inches apart. Since 1 inch is 400 miles half of an inch would be 200 miles!
1) The average increase in the level of CO2 emissions per year from years 2 to 4 is:
Average=[f(4)-f(2)]/(4-2)=(29,172.15-26,460)/2=2,712.15/2=1,356.075 metric tons. The first is false.
2) The average increase in the level of CO2 emissions per year from years 6 to 8 is:
Average=[f(8)-f(6)]/(8-6)=(35,458.93-32,162.29)/2=3,296.64/2=1,648.32 metric tons. The second is false.
3) The average increase in the level of CO2 emissions per year from years 4 to 6 is:
Average=[f(6)-f(4)]/(6-4)=(32,162.29-29,172.15)/2=2,990.14/2=1,495.07 metric tons. The third is false.
4) The average increase in the level of CO2 emissions per year from years 8 to 10 is:
Average=[f(10)-f(8)]/(10-8)=(39,093.47-35,458.93)/2=3,634.54/2=1,817.27 metric tons. The fourth is true.
Answer: Fourth option: The average increase in the level of CO2 emissions per year from years 8 to 10 is 1,817.27 metric tons.
Answer:
about 7.6 days long
Step-by-step explanation:
42 divided by 5.52 = about 7.6
