Answer with explanation:
For, a Matrix A , having eigenvector 'v' has eigenvalue =2
The order of matrix is not given.
It has one eigenvalue it means it is of order , 1×1.
→A=[a]
Determinant [a-k I]=0, where k is eigenvalue of the given matrix.
It is given that,
k=2
For, k=2, the matrix [a-2 I] will become singular,that is
→ Determinant |a-2 I|=0
→I=[1]
→a=2
Let , v be the corresponding eigenvector of the given eigenvalue.
→[a-I] v=0
→[2-1] v=[0]
→[v]=[0]
→v=0
Now, corresponding eigenvector(v), when eigenvalue is 2 =0
We have to find solution of the system
→Ax=v
→[2] x=0
→[2 x] =[0]
→x=0, is one solution of the system.
1.D 2. A 3.C 4.D
1 Is the monomial as it only contains one expression.
2. Is the difference of squares because something squared minus something squared.
3. Is standard because it is of the form
4. We know D is the not the monomial simply because its power is negative which means it does not fit the definition of a polynomial.
14.6 is the constant because no matter how many hours she will work (that number could change) it will always be a linear growth of 14.6.
Answer
Example 1 Solve for x and check: x + 5 = 3
Solution
Using the same procedures learned in chapter 2, we subtract 5 from each side of the equation obtaining
Example 2 Solve for x and check: - 3x = 12
Solution
Dividing each side by -3, we obtain
Step-by-step explanation: here is your anserw the let me know if it right
