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3 years ago

7

Evaluate (-7)2. p l e a s e a n s w e r q u i c k\

2 answers:

devlian [24]3 years ago

7 0

Answer:

(-7)2 = -14

Step-by-step explanation:

The parenthesis basically mean "multiply". So, this is a simple equation meaning -7 x 2. And remember, anytime we multiply a positive by a negative, you get a negative. So, simply multiply 7 x 2 = 14 and add a negative sign to make the solution true. So, -7 x 2 or (-7)2 = -14

Hope this helps! If you have any additional questions, please don't hesitate to ask me or your teacher to be sure you master the subject. Also thank you for the generous points!! Stay safe and please mark brainliest!!

zhenek [66]3 years ago

6 0

Answer:

-14

Step-by-step explanation:

just act as if -7 were positive then you know 7x2 = 14 cause' "()" means multiplication.

last, since 7 was negative in the first place then you turn your product back to a negative and you get -14

mark brainliest :)

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Find The distance between (-3,1) and (-1,6). If necessary,round to the nearest tenth.

kifflom [539]

Use distance formula:-

distance = sqrt [ (x2 - x1)^2 + (y2 - y1)^2) ]

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If p=(-3,-2) and q=(1,6) are the endpoints of the diameter of a circle find the equation of the circle

stira [4]

Answer:

<em>The equation of the circle (x +1) )² +(y-(2))² = (2(√5))²</em>

<em> or </em>

<em>The equation of the circle x² + 2 x + y² - 4 y = 15</em>

<u>Step-by-step explanation:</u>

Given points end Points are p(-3,-2) and q( 1,6)

<em>The distance of two points formula</em>

P Q = $\sqrt{x_{2} - x_{1})^{2} + ((y_{2} -y_{1})^{2} }$

P Q = $\sqrt{1 - (-3)^{2} + ((6 -(-2))^{2} }$

P Q = $\sqrt{16+64} = \sqrt{80}$

<em>The diameter 'd' = 2 r</em>

2 r = √80

= $\sqrt{16 X 5}$

= $4 \sqrt{5}$

<em> r = 2√5</em>

<em>Mid-point of two end points </em>

<em> </em> $(\frac{x_{1} + x_{2} }{2} , \frac{y_{1} +y_{2} }{2} ) = (\frac{-3+1}{2} ,\frac{-2 +6}{2} )$ <em></em>

<em> = (-1 ,2)</em>

<em>Mid-point of two end points = center of the circle</em>

<em> (h,k) = (-1 , 2)</em>

The equation of the circle

(x -h )² +(y-k)² = r²

<em> (x -(-1) )² +(y-(2))² = (2(√5))²</em>

<em> x² + 2 x + 1 + y² - 4 y + 4 = 20</em>

<em> x² + 2 x + y² - 4 y = 20 -5</em>

<em> x² + 2 x + y² - 4 y = 15</em>

<u><em>Final answer</em></u><em>:-</em>

<em>The equation of the circle (x +1) )² +(y-(2))² = (2(√5))²</em>

<em> or </em>

<em>The equation of the circle x² + 2 x + y² - 4 y = 15</em>

<em> </em>

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