Answer:
no solution
Step-by-step explanation:
6y≥42
Divide each side by 6
6y/6≥42/6
y≥7
Then solve the second one
4y+12≤0
Subtract 12 from each side
4y+12-12≤0-12
4y ≤-12
Divide each side by 4
4y/4 ≤-12/4
y ≤-3
There is no solution since there is no overlap
The cost would be about $560 when rounded to the nearest tent. Sorry if I’m no help
Answer:
Probability that randomly selected 4 persons all have insurance is = 0.1897
Step-by-step explanation:
Given that the probability of having an insurance equals 66%=0.66
Thus
Probability that person A has insurance = 0.66
Probability that person B has insurance = 0.66
Probability that person C has insurance = 0.66
Probability that person D has insurance = 0.66
Probability that randomly selected 4 persons all have insurance is
![P(A)\times P(B)\times P(C)\times P(D)\\\\=0.66\times 0.66\times 0.66\times 0.66=0.1897](https://tex.z-dn.net/?f=P%28A%29%5Ctimes%20P%28B%29%5Ctimes%20P%28C%29%5Ctimes%20P%28D%29%5C%5C%5C%5C%3D0.66%5Ctimes%200.66%5Ctimes%200.66%5Ctimes%200.66%3D0.1897)
So what there asking is what is the numerator after rewriting the fractions
They simply want you to write the equlivalent fractions so that the fractions can be added
<span>1/4+1/6
=3/12+2/12
------>1/4 and 1/6 were multiplied by 3, to give a common denominator of 12
= 5/12
------> With the same denominator the numerators were added</span>