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professor190 [17]
3 years ago
7

9x^2-1-(3x-2)^2=0 find the roots

Mathematics
1 answer:
Marizza181 [45]3 years ago
3 0

Step-by-step explanation:

<h2>=5/12</h2>

Make me as brain liest plz i need it

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What is this helppp 1/2 + 1/5
user100 [1]

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36. GEOMETRY Write an algebraic expression to
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Answer:

108 in²

Step-by-step explanation:

Area of a triangle is given as ½*base*height

The base of the given triangle = h + 6

height = h

Algebraic expression for its area = \frac{1}{2}*(h + 6)*h = \frac{1}{2}(h^2 + 6h) = \frac{h^2 + 6h}{2}

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4 years ago
What is the value of x? Enter your answer, as a decimal, in the box.<br><br> ___ cm
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Step-by-step explanation:

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6 0
3 years ago
Prove :<br>sin²θ + cos²θ = 1<br><br><br>thankyou ~​
Gnom [1K]

Answer:

See below

Step-by-step explanation:

Here we need to prove that ,

\sf\longrightarrow sin^2\theta + cos^2\theta = 1

Imagine a right angled triangle with one of its acute angle as \theta .

  • The side opposite to this angle will be perpendicular .
  • Also we know that ,

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\sf\longrightarrow cos\theta =\dfrac{b}{h}

And by Pythagoras theorem ,

\sf\longrightarrow h^2 = p^2+b^2 \dots (i)

Where the symbols have their usual meaning.

Now , taking LHS ,

\sf\longrightarrow sin^2\theta +cos^2\theta

  • Substituting the respective values,

\sf\longrightarrow \bigg(\dfrac{p}{h}\bigg)^2+\bigg(\dfrac{b}{h}\bigg)^2\\

\sf\longrightarrow \dfrac{p^2}{h^2}+\dfrac{b^2}{h^2}\\

\sf\longrightarrow \dfrac{p^2+b^2}{h^2}

  • From equation (i) ,

\sf\longrightarrow\cancel{ \dfrac{h^2}{h^2}}\\

\sf\longrightarrow \bf 1 = RHS

Since LHS = RHS ,

Hence Proved !

I hope this helps.

5 0
2 years ago
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