9x^2-1-(3x-2)^2=0 find the roots
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Answer:
Step-by-step explanation:
Hi there!
<u>What we need to know:</u>
- Linear equations are typically organized in slope-intercept form:
where m is the slope and b is the y-intercept (the value of y when x is 0)
- Perpendicular lines always have slopes that are negative reciprocals (ex. 3 and -1/3, 5/6 and -6/5, etc.)
<u>1) Determine the slope (m)</u>
y=x-9
Rewrite the equation
y=1x-9
Now, we can identify clearly that the slope of the line is 1. The negative reciprocal of 1 is -1, so therefore, the slope of a perpendicular line would be -1. Plug this into :
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<u>2) Determine the y-intercept (b)</u>
Plug in the given point (7,9) and solve for b
Add 7 to both sides to isolate b
Therefore, the y-intercept is 16. Plug this back into :
I hope this helps!