9x^2-1-(3x-2)^2=0 find the roots
1 answer:
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Answer:
y - 7 = 4(x - 35)
Step-by-step explanation:
The fundamental theorem of calculus states that:
= f(x).
So using the fundamental theorem of calculus, you can find that h'(x) = f(x).
The question tells you that f(x) is periodic with a period of 8, so f(x) repeats itself every 8 units.
Using this, you can find that the slope of h(x) at x = 35 is the same as the slope of h(x) at x = 3, which is 4.
The slope of h(x) at x = 35 is 4.
Now I have to find the value of h(x) when x = 35. It is the area under f(x) from 0 to 35.
The area underneath f(x) from 0 to 35 is 7. When x = 35, h(x) = 7.
Now use the point-slope formula to write the equation of the tangent line.
The answer is <u>y - 7 = 4(x - 35)</u>