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OLga [1]
3 years ago
10

The density of air under ordinary conditions at 25 degrees * C is 1.19g / L . How many kilograms of air are in a room that measu

res 9.0ft * 11.0ft and has a 10.0 ft ceiling?
Chemistry
1 answer:
professor190 [17]3 years ago
5 0

Answer:

33.3 kg of air

Explanation:

This is a problem of conversion unit.

Density is mass / volume

Therefore we have to calculate the volume in the room, to be multiply by density. That answer will be the mass of air.

Volume of the room → 9 ft . 11 ft . 10 ft = 990 ft³

Density is in g/L, therefore we have to convert the ft³ to dm³ (1 dm³ = 1L)

990 ft³ . 28.3 dm³ / 1ft³ = 28017 dm³ → 28017 L

This is the volume of the room, if we replace it in the density formula we can know the mass of air in g.

1.19 g/L = Mass of air / 28017 L

Mass of air = 28017 L .  1.19 g/L → 33340 g of air

Finally, let's convert the mass in g to kg → 33340 g . 1kg / 1000 g = 33.3 kg

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Why is the addition of cold distilled water to the container holding the aspirin you are trying to isolate a necessary step and
Rudik [331]

Answer:

The aspirin is more soluble in ethanol than water - the water helps the crystals separate from solution.

Explanation:

Hope this helps!

3 0
2 years ago
A student sets up the following equation to convert a measurement.
dybincka [34]

Answer:

\frac{1 m}{100 cm}

Explanation:

The final answer has a different set of units. In particular, meters (m) changes to centimeters (cm). To make this change, you need to multiply the first value by proportions.

When writing these proportions, it is important that they are arranged in a way that allows for the cancellation of units. For instance, since m is located in the denominator, it must be located in the numerator of the conversion.

<u>Proportion:</u>

1 m = 100 cm

The full expression:

<h3>-1.7*10^5\frac{V}{m}  ·  \frac{1 m}{100 cm}  =  ? \frac{V}{cm}</h3><h2>                 ^</h2>

As you can see, the old unit (m) cancels out and you are left with cm in the denominator.

7 0
2 years ago
Which element forms a chloride of the type XCl2
Nat2105 [25]

Explanation:

Element X forms a chloride with the formula XCl 2 , which is a solid with a high melting point. X would most likely be in the same group of the Periodic Table as. (a) Na (b) Mg (c) Al (d) Si. the answer is Mg .

8 0
2 years ago
1. The heat of fusion for the ice-water phase transition is 335 kJ/kg at 0°C and 1 bar. The density of water is 1000 kg/m3 at th
vodomira [7]

Answer:

Expression for the change of melting temperature with pressure..> T₂ = T₁exp(-(P₂-P₁)/(3.61x10⁹ Pa), Freezing Point = 0°C

Explanation:

Derivation from state postulate

Using the state postulate, take the specific entropy,  , for a homogeneous substance to be a function of specific volume  and temperature  .

ds = (partial s/partial v)(t) dv + (partial s/partial T)(v) dT

During a phase change, the temperature is constant, so

ds = (partial s/partial v)(T)  dv

Using the appropriate Maxwell relation gives

ds = (partial P/partial T)(v) dv

s(β) – s(aplαha) = dP/dT (v(β) – v(α))

dP/dT = s(β) – s(α)/v(β) – v(α) = Δs/Δv

Here Δs and Δv are respectively the change in specific entropy and specific volume from the initial phase α to the final phase β.

For a closed system undergoing an internally reversible process, the first law is

du = δq – δw = Tds - Pdv

Using the definition of specific enthalpy, h and the fact that the temperature and pressure are constant, we have

du + Pdv = dh Tds,

ds = dh/T,

Δs = Δh/T = L/T

After substitution of this result into the derivative of the pressure, one finds

dp/dT = L/TΔv

<u>This last equation is the Clapeyron equation.</u>

a)

(dP/dT) = dH/TdV => dP/dlnT = dH/dV

=> dP/dlnT = dH/dV = [H(liquid) - H(solid)]/[V(liquid) - V(solid)]

= [335,000 J/kg]/[1000⁻¹ - 915⁻¹ m³/kg]

= -3.61x10⁹ J/m³ = -3.61x10⁹ Pa

=> P₂ = P₁ - 3.61x10⁹ ln(T₂/T₁) Pa

or

T₂ = T₁exp(-(P₂-P₁)/(3.61x10⁹ Pa)

b) if the pressure in Denver is 84.6 kPa:

T₂(freezing) = 273.15exp[-(84,600-100,000)/(3.61x10⁹)]

≅ 273.15 = 0°C T₁(freezing) essentially no change

5 0
3 years ago
What kind of questions can science answer
IrinaK [193]

Answer:

hypothesis

Explanation:

a question that can be answered wity a hypothesis is a question a scientist can answer

5 0
3 years ago
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