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Rina8888 [55]
2 years ago
11

An angle of 90° measures (___) Pi radians.An angle of -pi/5 radians measures ____?°.

Mathematics
1 answer:
a_sh-v [17]2 years ago
4 0

\huge \bf༆ Answer ༄

Conversion from degree to radian ~

  • \boxed{ \sf{ \frac{\pi}{180} \times  \theta }}

  • \sf \dfrac{\pi}{180 } \times 90

  • \sf \dfrac{\pi}{2}  \:  \: rad

Conversion from radians to degree ~

  • \boxed{ \sf{ \frac{180}{\pi}  \times  \theta}}

  • \sf \dfrac{180}{\pi}  \times   - \dfrac{ \pi}{5}

  • \sf  - 36 \degree

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Which expression is equivalent to 8 square root 6 in square root form
Fiesta28 [93]

Answer:

2 square root 2

Step-by-step explanation:

it is equal to 2.828 approximately. Squares root of a number is the number, which, on multiplying by itself gives the original number. Since 8 is not a perfect square, hence the value is represented in root form.

5 0
3 years ago
A square has a length of 13m, find its area A. 1699m² B. 169m² C. 196m² D. 169m² I will mark you as brainliest
mars1129 [50]

Answer: 169 m²

Step-by-step explanation:

The area of a square can be found by taking a side length(13), and squaring it, to get, in this case, 139.

Hope it helps <3

4 0
3 years ago
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Generate the first five terms in the sequence using the explicit formula. yn=-5n-6
alexandr402 [8]
Given that n starts from 1,
y₁ = -5(1) - 6 = -11
y₂ = -5(2) - 6 = -16
y₃ = -5(3) - 6 = -21
y₄ = -5(4) - 6 = -26
y₅ = -5(5) - 6 = -31
8 0
3 years ago
When does a parabola open upward
RUDIKE [14]

Answer:

If the x is squared, the parabola is vertical (opens up or down). If the y is squared, it is horizontal (opens left or right). If a is positive, the parabola opens up or to the right. If it is negative, it opens down or to the left.

Step-by-step explanation:

8 0
3 years ago
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For i≥1 , let Xi∼G1/2 be distributed Geometrically with parameter 1/2 . Define Yn=1n−−√∑i=1n(Xi−2) Approximate P(−1≤Yn≤2) with l
murzikaleks [220]

Answer:

The answer is "0.68".

Step-by-step explanation:

Given value:

X_i \sim \frac{G_1}{2}

E(X_i)=2 \\

Var (X_i)= \frac{1- \frac{1}{2}}{(\frac{1}{2})^2}\\

             = \frac{ \frac{2-1}{2}}{\frac{1}{4}}\\\\= \frac{ \frac{1}{2}}{\frac{1}{4}}\\\\= \frac{1}{2} \times \frac{4}{1}\\\\= \frac{4}{2}\\\\=2

Now we calculate the \bar X \sim N(2, \sqrt{\frac{2}{n}})\\

\to \frac{\bar X - 2}{\sqrt{\frac{2}{n}}}  \sim  N(0, 1)\\

\to \sum^n_{i=1}  \frac{X_i - 2}{n}  \times\sqrt{\frac{n}{2}}}  \sim  N(0, 1)\\\\\to  \sum^n_{i=1}  \frac{X_i - 2}{\sqrt{2n}}  \sim  N(0, 1)\\

\to Z_n = \frac{1}{\sqrt{n}} \sum^n_{i=1} (X_i -2) \sim N(0, 2)\\

\to P(-1 \leq X_n \leq 2)  = P(Z_n \leq Z) -P(Z_n \leq -1) \\\\

                               = 0.92 -0.24\\\\= 0.68

6 0
3 years ago
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