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pantera1 [17]
2 years ago
12

Five times a number is ten more than three times the number. Find the number​

Mathematics
2 answers:
andriy [413]2 years ago
7 0

Answer:

x = 5

Step-by-step explanation:

Number = x

5x = 10 + 3x  

2x = 10

x = 5

natita [175]2 years ago
4 0

5x = 10 + 3x

5x - 3x = 10

2x = 10

x = 5

To check

5(5) = 10 + 3(5)

25 = 10 + 15

25 = 25

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If 10% off is 20 what is 23% off?
stepan [7]
23% off is 46 because 10%is 20 so 20% is 40 and 1% is 2 because 20/10 is 2 so the answe is 46
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Larry spent 1/2 of his money on a camera and another 1/8 on a radio. the camera cost $120 more than the radio. how much money di
elena-s [515]
Let, his original money = x
It would be: x * 1/2 = 120 
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In short, Your Answer would be $240

Hope this helps!
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3 years ago
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V= 2i +9j Find ||9v||
Korvikt [17]

Answer:

9\sqrt{85}

Step-by-step explanation:

9v = 9(2i + 9j) = 18i + 81j

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8 0
3 years ago
How do you factor 125-x^3?
xz_007 [3.2K]

Step-by-step explanation:

We have

125 - x {}^{3}

First, 125 is a perfect cube because

5 \times 5 \times 5 = 125

and

x^3 is a perfect cube because

x \times  x \times x = x {}^{3}

so we can use the difference of cubes identity

( {x}^{3}  -  {y}^{3} ) = (x - y)( {x}^{2}  + xy +  {y}^{2} )

Let say we have two perfect cubes:

64 because 8×8×8=64

and 27 because 3×3×3=27 and let subtract

64 - 27

we know that

64 - 27 = 37

but using the difference of cubes identity we should get the same thing.

Remeber cube root of 64 is 4 and cube root of 27 is 3 so we have

(4 - 3)( {4}^{2}  + 4(3) + 3 {}^{2} )

1(16 + 12 + 9) = 1(37) = 37

So the difference of cubes works for real numbers. This is a good way to help remeber the identity using real numbers.

Back on to the topic,

we know that 5 is cube root of 125 and x is the cube root of x^3 so we have

(5 - x)( {5}^{2}  + 5x +  {x}^{2} ) =

(5 - x)(25 + 5x +  {x}^{2} )

3 0
2 years ago
Read 2 more answers
Plisss help on my assesment
Anon25 [30]

Answer:

The first one is equivalent [the 6x+48 = 2(3x+24)] and the second one is <u>NOT</u> equivalent [the 7x+21 ≠ 2(5x+3)]

Step-by-step explanation:

Just follow distributive property to solve these. You can ignore the first expression in both until you have to compare the answers.

1. 6x+48 and 2(3x+24)

2(3x+24) ---> 2(3x) + 2(24) ---> <u>6x + 48</u>

Bring in the first expression ~ <u>6x+48 and 6x+48 </u>

They are the same, so they are equivalent

2. 7x+21 and 2(5x+3)

2(5x+3) ---> 2(5x) + 2(3) ----> 10x + 6

Bring in the first expression ~ <u>7x+21 and 10x + 6</u>

They are NOT the same, so they are NOT equivalent

6 0
3 years ago
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