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crimeas [40]
3 years ago
15

a passenger on cruise between San Juan, Puerto Rico and Miami, Florida accidentally drops a souvenir metal cube over the side of

the boat, into the water. Each side of the metal cube measures 1 meter. The cube promptly sinks to the deepest part of the Puero Rico Trench. Once at the bottom, what pressure does the cube experience? Neglect Atmospheric Pressure. Use wikipedia to see depth of Trench!
Physics
1 answer:
Viefleur [7K]3 years ago
6 0

Answer:

P = 84.1 MPa

Explanation:

  • The pressure at the bottom of column of of salt water of height h, is given by the following expression:

       P = \rho * g * h  (1)

       where ρ = density of salt water (in Kg/m³),

       g = acceleration due to  gravity  (in m/s²)

       h = height of the column of water.

  • Replacing by their values in (1):

      P = \rho * g * h  = 1023.6kg/m3*9.8m/s2*8380m = 84.1 MPa  (2)

  • Neglecting the atmospheric pressure, the pressure on the cube at the bottom of Puerto Rico Trench is given by (2):
  • P = 84.1 MPa.
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Answer:

it will take for the sphere to increase in potential by 1500 V, 503.71 s.

Explanation:

The charge on the sphere after t seconds is:

q = (1.0000049 - 1.0000000) t = 0.0000049 t

The voltage on the surface is

V = k * \frac{q}{R} = k 0.0000049 t / R

solve for t

t = (R*V) / (0.0000049 k) = (0.12 * 1500) / (0.0000049 * 9e^{9}) = 503.71 s

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4 years ago
Sphere 1 with radius R_1 has positive charge q, Sphere 2 with radius 4.50 R_1 is far from sphere 1 and initially uncharged. The
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Answer:

Explanation:

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b )

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Answer:

14 km

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