1) The mass of the continent is
2) The kinetic energy of the continent is 274.8 J
3) The speed of the jogger must be 2.76 m/s
Explanation:
1)
The continent is a slab of side 5900 km (so the surface is 5900 x 5900, assuming it is a square) and depth 26 km, therefore its volume is:
The mass of the continent is given by
where:
is its density
is its volume
Substituting, we find the mass:
2)
To find the kinetic energy, we need to convert the speed of the continent into m/s first.
The speed is
v = 1.6 cm/year
And we have:
1.6 cm = 0.016 m
So, the speed is
Now we can find the kinetic energy of the continent, which is given by
where
is the mass
is the speed
Substituting,
3)
The jogger in this part has the same kinetic energy of the continent, so
K = 274.8 J
And its mass is
m = 72 kg
We can write his kinetic energy as
where
v is the speed of the man
And solving the equation for v, we find his speed:
Learn more about kinetic energy:
brainly.com/question/6536722
#LearnwithBrainly
Answer:
a) M₂ ( the object that is stationary) b) 3 times c) the velocity is to the left
Explanation:
let the object in motion = M₁, object stationary = M₂, the initial velocity of the M₁ = U₁, since the second object is at rest U₂ = 0, final velocity of the M₁ = V₁ and final velocity for M₂ = V₂
Using conservation law of momentum:
M₁U₁ = M₁V₁ + M₂V₂ since the second body is at rest
also
V₂ = U₁ / 2 and the collision is elastic meaning
U₁ = V₂ - V₁
U₁ = U₁ / 2 - V₁
V₁ = -U₁/2
substitute V₁ into the first equation
M₁U₁ = M₁V₁ + M₂V₂
M₁U₁ = M₁ (-U₁/2) + M₂ ( U₁/2)
collect the like terms
M₁U₁ + M₁ (U₁/2) = M₂(U₁/2)
3/2(M₁ U₁) = M₂ (U₁/2)
divide both side by U₁/2
3 M₁ = M₂
b) M₂ = 3 M₁
M₂ is three times M₁
c) V₁ = -U₁/2
since V₁ is negative, the velocity will be to the left
Answer
The answer and procedures of the exercise are attached in the following archives.
Step-by-step explanation:
You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.
Answer:
y₀ = 10.625 m
Explanation:
For this exercise we will use the kinematic relations, where the upward direction is positive.
y = y₀ + v₀ t - ½ g t²
in the exercise they indicate the initial velocity v₀ = 8 m / s.
when the rock reaches the ground its height is zero
0 = y₀ + v₀ t - ½ g t²
y₀i = -v₀ t + ½ g t²
let's calculate
y₀ = - 8 2.5 + ½ 9.8 2.5²
y₀ = 10.625 m