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vladimir2022 [97]

2 years ago

10

What is the relationship between frequency and degree of refraction?

1 answer:

r-ruslan [8.4K]2 years ago

8 0

Answer: "The index of refraction of any material (besides vacuum) varies slightly with the frequency of light: the higher the frequency, the greater the index of refraction. Since red light has a lower frequency than violet, its index of refraction will be lower.

Explanation:

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A stone is thrown vertically up. What kind of energy did the stone have initially? What happens to this energy as the stone asce

Alex

Answer:

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Explanation:

kinetic turns to potential as it gains height

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3 years ago

Suppose that the acceleration of a model rocket is proportional to the difference between 160 ft/sec and the rocket's velocity.

Levart [38]

Answer:

Explanation:

Given ,

dv / dt = k ( 160 - v )

dv / ( 160 - v ) = kdt

ln ( 160 - v ) = kt + c , where c is a constant

when t = 0 , v = 0

Putting the values , we have

c = ln 160

ln ( 160 - v ) = kt + ln 160

ln ( 160 - v / 160 ) = kt

(160 - v ) / 160 = $e^{kt}$

1 - v / 160 = $e^{kt }$

v / 160 = 1 - $e^{kt }$

v = 160 ( 1 - $e^{kt }$ )

differentiating ,

dv / dt = - 160k $e^{kt }$

acceleration a = - 160k $e^{kt }$

given when t = 0 , a = 280

280 = - 160 k

k = - 175

a = - 160 x - 175 $e^{kt}$

a = 28000 $e^{kt}$

when a = 128 t = ?

128 = 28000 $e^{kt}$

$e^{kt }$ = .00457

5 0

2 years ago

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3 years ago

A diffraction grating produces a first-order bright fringe that is 0.18 m away from the central bright fringe on a flat screen.

Georgia [21]

Answer:

The wavelength of the light is 562.5 nm

Solution:

As per the question:

Order, n = 1

Slit separation, d = $2.5\times 10^{- 6}\ m$

Distance from the bright fringe, y = 0.18 m

Distance between the screen and the grating, D = 0.8 m

Now,

We know from the eqn for diffraction:

$n\lambda = dsin\theta$

n = 1

$\lambda = dsin\theta$ (1)

Also,

For very small angle, $\theta$ :

$sin\theta$ ≈ $tan\theta = \frac{y}{D} = \frac{0.18}{0.8} = 0.225$

Using the above value in eqn (1):

$\lambda = 2.5\times 10^{- 6}\times 0.225 = 5.625\times 10^{- 7}\ m = 562.5\ nm$

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2 years ago

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3 years ago

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