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vlabodo [156]
2 years ago
6

Meredith works at a blood bank. She needs to write a report of the ratio of type-A blood donated to type-O blood donated, but sh

e lost this month's logs that had the quantities. She knows that last month 25 pints of type-A blood were donated and 42 pints of type-O blood were donated. She remembers that this month 55 pints of type-A blood were donated. If the ratio held true for this month, how can Meredith determine the amount of type-O blood donated?
Mathematics
1 answer:
kari74 [83]2 years ago
6 0

Answer:

uh,

Step-by-step explanation:

42-55=7   7+25=32

32:55

i am sorry if this doesn't help!~

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Does anyone know the answer I NEED the explanation. The answer is not D
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Answer: A

Step-by-step explanation:

I am not entirely sure, but the answer would most likely be A. Since the coordinates for the tops of the triangles are the same, I would assume that the bottom parts would be the same as well. This is probably not the correct answer, but it's my best attempt. I'm apologize in advance if it was not the answer you were looking for.

8 0
3 years ago
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Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%. Find
Papessa [141]

Answer:

1) \text{P(at least one boy and one girl)}=\frac{3}{4}

2) \text{P(at least one boy and one girl)}=\frac{3}{8}

3) \text{P(at least two girls)}=\frac{1}{2}

Step-by-step explanation:

Given : Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%.

To  Find : The probability of each event.  

1) P(at least one boy and one girl)

2) P(two boys and one girl)

3) P(at least two girls)        

Solution :

Let's represent a boy with B and a girl with G

Mr. and Mrs. Romero are expecting triplets.

The possibility of having triplet is

BBB, BBG, BGB, BGG, GBB, GBG, GGB, GGG

Total outcome = 8

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}

1) P(at least one boy and one girl)

Favorable outcome =  BBG, BGB, BGG, GBB, GBG, GGB=6

\text{P(at least one boy and one girl)}=\frac{6}{8}

\text{P(at least one boy and one girl)}=\frac{3}{4}

2) P(at least one boy and one girl)

Favorable outcome =  BBG, BGB, GBB=3

\text{P(at least one boy and one girl)}=\frac{3}{8}

3) P(at least two girls)

Favorable outcome = BGG, GBG, GGB, GGG=4

\text{P(at least two girls)}=\frac{4}{8}

\text{P(at least two girls)}=\frac{1}{2}

4 0
4 years ago
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4 0
3 years ago
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inn [45]

Answer:

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Step-by-step explanation:

Our total is x.

Maysa took half of the cherries, so there is .5x left.

Nabilla took half of the remaining, so that is .5*0.5x, which is .25x

Abdulla took 3.

Your equation is:

.25x-3=5

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DerKrebs [107]
D= rt
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