Answer:
The other distances are 400 ft and 750 ft.
Step-by-step explanation:
a + b + c = 2000
a + b + 850 = 2000
a + b = 1150 Equation 1
a^2 + b^2 = c^2
a^2 + b^2 = 850^2
a^2 + b^2 = 722,500 Equation 2
a + b = 1150
a^2 + b^2 = 722,500
a = 1150 - b
(1150 - b)^2 + b^2 = 722,500
1,322,500 - 2300b + b^2 + b^2 = 722,500
2b^2 - 2300b + 600,000 = 0
b^2 - 1150b + 300,000 = 0
![x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}](https://tex.z-dn.net/?f=%20x%20%3D%20%5Cdfrac%7B-b%20%5Cpm%20%5Csqrt%7Bb%5E2%20-%204ac%7D%7D%7B2a%7D%20)
![x = \dfrac{-(-1150) \pm \sqrt{(-1150)^2 - 4(1)(300,000)}}{2(1)}](https://tex.z-dn.net/?f=%20x%20%3D%20%5Cdfrac%7B-%28-1150%29%20%5Cpm%20%5Csqrt%7B%28-1150%29%5E2%20-%204%281%29%28300%2C000%29%7D%7D%7B2%281%29%7D%20)
![x = \dfrac{1150 \pm \sqrt{1,322,500 - 1,200,000}}{2}](https://tex.z-dn.net/?f=%20x%20%3D%20%5Cdfrac%7B1150%20%5Cpm%20%5Csqrt%7B1%2C322%2C500%20-%201%2C200%2C000%7D%7D%7B2%7D%20)
![x = \dfrac{1150 \pm \sqrt{122,500}}{2}](https://tex.z-dn.net/?f=%20x%20%3D%20%5Cdfrac%7B1150%20%5Cpm%20%5Csqrt%7B122%2C500%7D%7D%7B2%7D%20)
![x = \dfrac{1150 \pm 350}{2}](https://tex.z-dn.net/?f=x%20%3D%20%5Cdfrac%7B1150%20%5Cpm%20350%7D%7B2%7D)
![x = \dfrac{1500}{2}~~~or~~~x = \dfrac{800}{2}](https://tex.z-dn.net/?f=%20x%20%3D%20%5Cdfrac%7B1500%7D%7B2%7D~~~or~~~x%20%3D%20%5Cdfrac%7B800%7D%7B2%7D%20)
x = 750 or x = 400
Answer: The other distances are 400 ft and 750 ft.
The answer is 13.1
Ever need help I am here
Answer:
the answer is 1 1/5
Step-by-step explanation:
what i did was 9/5 times 2/3 which got me 1 1/5
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Answer:
B. f−1(x) = The quantity of 4x plus 3, divided by 5
Step-by-step explanation:
Given
![f(x) = \frac{5x-3}{4}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7B5x-3%7D%7B4%7D)
We have to find the inverse of the function
![Let\\f(x) = y\\y=\frac{5x-3}{4}\\4y=5x-3\\4y+3=5x\\\frac{4y+3}{5} =y](https://tex.z-dn.net/?f=Let%5C%5Cf%28x%29%20%3D%20y%5C%5Cy%3D%5Cfrac%7B5x-3%7D%7B4%7D%5C%5C4y%3D5x-3%5C%5C4y%2B3%3D5x%5C%5C%5Cfrac%7B4y%2B3%7D%7B5%7D%20%3Dy)
So, the inverse of f(x) is:
![\frac{4y+3}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B4y%2B3%7D%7B5%7D)
Hence,
The correct answer is:
<u>B. f−1(x) = The quantity of 4x plus 3, divided by 5 ..</u>
Since x is on the right side of the equation, switch the sides so it is on the left side of the equation.<span><span>6<span>x<span>−3</span></span></span>=<span>136</span></span>Create equivalent expressions in the equation that all have equal bases.<span><span>6<span>x<span>−3</span></span></span>=<span>6<span>−2</span></span></span>Since the bases are the same, then two expressions are only equal if the exponents are also equal.<span><span>x<span>−3</span></span>=<span>−2</span></span>Move all terms not containing x to the right side of the equation..Since <span>−3</span> does not contain the variable to solve for, move it to the right side of the equation by adding 3 to both sides.<span>x=<span>3<span>−2</span></span></span>Subtract 2 from 3 to get 1.<span>x=<span>1</span></span>