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Elan Coil [88]
2 years ago
8

What type of lens is a flat lens?

Physics
2 answers:
Bogdan [553]2 years ago
7 0
A flat lens is a flat lens
vodomira [7]2 years ago
5 0

Answer:

A flat lens is a lens whose flat shape allows it to provide distortion-free imaging, potentially with arbitrarily-large apertures. The term is also used to refer to other lenses that provide a negative index of refraction. Flat lenses require a refractive index close to −1 over a broad angular range.

Explanation:

Plano - A plano lens is a flat lens. This is used when one side is flat and the other side is concave or convex. You can think of flat as a "plain."

this the answer

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Two forces whose resultant is 100N are at right angle to eachother. if one of them makes an angle of 30° with the resultant, det
mihalych1998 [28]

Let <em>F₁ </em>and <em>F₂</em> denote the two forces, and <em>R</em> the resultant force.

<em>F₁ </em>and <em>F₂</em> point perpendicularly to one another, so their dot product is

<em>F₁ </em>• <em>F₂</em> = 0

<em />

We're given that one of these vectors, say <em>F₁</em>, makes an angle with <em>R</em> of 30°, so that

<em>F₁</em> • <em>R</em> = ||<em>F₁</em>|| ||<em>R</em>|| cos(30°)

But we also have

<em>F₁</em> • <em>R</em> = <em>F₁ </em>• (<em>F₁ </em>+ <em>F₂</em>) = (<em>F₁ </em>• <em>F₁</em>) + (<em>F₁ </em>• <em>F₂</em>) = <em>F₁ </em>• <em>F₁ </em>=<em> </em>||<em>F₁</em>||²

So, knowing that ||<em>R</em>|| = 100 N, we get that

(100 N) ||<em>F₁</em>|| cos(30°) = ||<em>F₁</em>||²

(100 N) cos(30°) = ||<em>F₁</em>||

||<em>F₁</em>|| ≈ 86.6 N

(And the same would be true for <em>F₂</em>.)

8 0
3 years ago
How is potential energy, kenetic energy, and total energy related?
avanturin [10]

Answer:

add them together then they

6 0
3 years ago
Please answer this question​
FinnZ [79.3K]

Answer:

The circuits that were made previously were large and bulky, consisting of circuit components like resistor, capacitor, inductor, transistor, diodes, etc., which were connected with copper wires.

Explanation:

I am in confusion with mono electronic circuit and I am not want to made u confused person.

I am really sorry brother.

:-befrank

4 0
2 years ago
A sports car accelerates at 2.80 m/s2 along a straight road. At t1 = 5.00s and t2 = 5.50 s it passes two marks that are 35.0 m a
harina [27]

Explanation:

Using kinematics,

s = ut + 0.5at².

We have s = 35.0m, t = 0.50s, a = 2.80m/s².

Substitute in the variables, we have u = 69.3m/s.

This u is only the initial velocity at t1. To find the velocity at t0, we apply a different kinematics equation with different values:

We have t = 5.00s, a = 2.80m/s², v = 69.3m/s.

Using kinematics,

v = u + at.

Substitute in the variables, we have u = 55.3m/s.

Hence the car's initial velocity is 55.3m/s.

7 0
3 years ago
Bob creates an instrument that is able to play C4 (261.63 Hz). He does some analysis with the sound equipment and it shows that
Dmitry [639]

Answer:

It could be a stringed instrument or an open pipe.

Explanation:

Let v be the speed of sound, y be wavelength and f be frequency.

v = yf

f= v/y; v is constant.

In a stringed instrument, the fundamental frequency note is heard when the length of the string, l = y/2; y= 2l

f′= v/2l

The second harmonic is heard when l= y

f"= v/y

...

f'''= 3v/2l

We can infer that f"= 2f'

f'''= 3f'

This is similar to the values in the question as;

523.26 =2(261.63) and so on.

Same thing happens with open pipes.

4 0
2 years ago
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