The initial velocity of the train is 12.56 m/s.
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Initial velocity</h3>
The initial velocity of the train can be determined by using the first kinematic equation as shown below;
v = u + at
u = v - at
where;
- v is the final velocity = 110 km/h = 30.56 m/s
- u is the initial velocity
u = 30.56 - (36 x 0.5)
u = 12.56 m/s
Thus, the initial velocity of the train is 12.56 m/s.
Learn more about initial velocity here: brainly.com/question/19365526
Answer:
Explanation:
initial velocity, u = 8 m/s
vertical height, h = 1 m
θ = 40°
Let the horizontal distance is d and the time taken is t.
Use second equation of motion in vertical direction
h = ut + 1/2 at²
1 = 8 Sin 40 x t + 0.5 x 9.8 t²
1 = 5.14 t - 4.9t²
4.9t² - 5.14 t + 1 = 0
so, t = 0.26 s (smaller value)
So, the horizontal distance is
d = u cos 40 x t
d = 8 cos 40 x 0.26
d = 1.6 m
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