How many World Cups have the U.S. Women's National Soccer Team won?

May I please get some help?

xxMikexx [17]

B is the correct q2ureire awej\

3 0

3 years ago

How do throns Mostly likely help a plant to survive

jok3333 [9.3K]

Thorns protect plants from insects or harmful bugs.

3 0

3 years ago

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A block of mass m moving with a velocity v collides with a mass 2m at rest. Consider the collision is elastic, we have to find t

lions [1.4K]

Answer:

$vf_{1} =\frac{1}{3} v$ :Final block velocity (toward the left)

$vf_{2} =\frac{2}{3} v$ :Final mass velocity (to the right)

Explanation:

To solve this problem we apply the theory of shocks:

In an elastic shock the kinetic energy and the amount of linear movement or momentum are conserved.

Because the shock is elastic, the coefficient of elastic restitution (e) is equal to 1.

Principle of conservation of the momentum:

m1vi1+m2vi2=m1vf1+m2vf2 Equation 1

Formula to calculate the coefficient of elastic restitution (e):

$e=\frac{vf_{2}-vf_{1} }{vi_{1}-vi_{2} }$ Equation 2

m1: Block mass

m2: mass of the body that collides with the block

Vi1,vf1: initial, final velocity of the block

Vi2,vf2: initial, final velocity of the body that collides with the block

Of the problem data we know that:

m1=m , m2 = 2m, vi1=v and vi2=0, then, we replace this information in equation (1) :

mv+0=mvf1+2mvf2 we divide by m:

v=vf1+2vf2 Equation (3)

Because the shock is elastic, the coefficient of elastic restitution (e) is equal to 1,then , we we replace this information in equation (2)

$1=\frac{vf_{2}-vf_{1} }{v-0}$

v=vf2-vf1 Equation (4)

vf2=v+vf1 Equation (5)

We replace the equation 5 in the equation (3)

v=vf1+2(v+vf1)

v=vf1+2v+2vf1

-3vf1=v

$vf_{1} = -\frac{1}{3} v$

We replace Vf1=(-1/3)v in the equation (5):

$vf_{2} =v-\frac{1}{3} v$

$vf_{2} =\frac{2}{3} v$

Answer;

$vf_{1} =\frac{1}{3} v$ :Final block velocity (toward the left)

$vf_{2} =\frac{2}{3} v$ :Final mass velocity (to the right)

5 0

2 years ago

suppose an insect dropped off a leaf and falls to the ground. consider the forces acting on the insect when it starts to fall, w

Naddika [18.5K]

Answer:

A) When the insect starts to fall.

Assuming that the little insect can not do anything (he/she does not have wings or anything like that) the only force acting on the insect will be:

Gravitational force: Is the force that pulls down the insect.

Air resistance: As the insect starts to move, the air will try to oppose to that motion.

B) When the insect falls at a constant speed.

This will happen when the air resistance equals in magnitude (but in opposite direction) the gravitational force.

Now the net force is zero, so the insect is not accelerated anymore, which means that the insect moves at a constant speed.

And the fact that the net force is zero does not mean that the gravitational force and the air resistance are "not acting" on the insect, this means that those forces are not having any effect in the dynamics of the insect's motion.

C) When it lands.

When the insect lands, there is a new force that appears, the normal force of the ground that opposes to the movement of the insect through it.

As the insect comes to stop (because he hits the ground) the air resistance does not longer act on it, so now the normal force of the ground is equal in magnitude (but in opposite direction) to the gravitational force, then the net force is zero.

D) When is there a net force acting and in what direction?

The only time that is a net force acting, is when the insect starts to fall, where the gravitational force is accelerating the insect downwards.

E) What force pair is there when the insect lands?

The force pair is the gravitational force, and the reaction, the normal force of the ground.

4 0

3 years ago

What type of galaxy is pictured below? irregular spiral lens elliptical

pychu [463]

Answer: The picture shows the elliptical galaxy.

Explanation :

There are three types of galaxies i.e.

Irregular galaxy

Spiral galaxy

Elliptical galaxy

The given picture shows an elliptical galaxy. It has a shape of the spheroid or elongated sphere. As we go farther away from the center, the brightness goes on decreasing.

Hence, the correct option is (c) " elliptical galaxy ".

7 0

3 years ago

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