2 years ago

CAN SOMEONE HELP ME PLEASE ASAP!?

Mathematics

1 answer:

loris [4]2 years ago

5 0

Answer:

for me the answer was c not sure if you will get it correct but again the answer for me was C

Step-by-step explanation:

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Anyone know how to solve this??

Tom [10]

$Given : \frac{(x^\frac{2}{5})^9\;.\;(x^\frac{-4}{15})}{x^\frac{1}{3}}$

$\implies {(x^\frac{18}{5})\;.\; (x^\frac{-4}{15})}\;.\;(x^\frac{-1}{3})$

$\implies x^(^\frac{18}{5} ^-^\frac{4}{15}^-^\frac{1}{3}^)$

$\implies x^(^(^\frac{54 - 4}{15}^)^-^\frac{1}{3}^) = x^(^(^\frac{50}{15}^)^-^\frac{1}{3}^) = x^(^(^\frac{10}{3}^)^-^\frac{1}{3}^) = x^(^\frac{9}{3}^) = x^3$

$\implies x^k = x^3$

$\implies k = 3$

7 0

3 years ago

Helppp!!!! please!!!

Vitek1552 [10]

Answer:

d. 15 square yard

Step-by-step explanation:

$area \: of \: shape \\ = \frac{1}{2} \times base \times height \\ \\ = \frac{1}{2} \times 10 \times 3 \\ \\ = \frac{1}{2} \times 30 \\ \\ = 15 \: {yd}^{2}$