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Greeley [361]
2 years ago
13

When an object moves, stops moving, changes speed, or changes direction, how do scientists describe that condition? Question 1 o

ptions: a balanced set of forces unbalanced forces frictional force stable factors.
Physics
1 answer:
Dominik [7]2 years ago
4 0

If an object moves, stops, changes speed, or even changes direction, then that condition represents the unbalanced force condition.

Unbalanced Force:

The unbalanced force is the magnitude of the net force that tends to cause the motion of objects. It is nothing but the greater amount of force to be applied to the object to displace the object in either direction.

If an object is moving, stopping, changing the speed, or changing the direction, then such activities directly show that the object is changing its state of motion. And the change in the motion is only caused when there is some magnitude of force associated with it.

  • When the magnitude of forces applied on an object such that one force is greater than another in a specific direction, then such forces are known as unbalanced forces.
  • Unbalanced forces cause motion, which means a body can move, stop or even can change its direction due to the unbalanced force.

Thus, we can conclude that if an object moves, stops, changes speed, or even changes direction, then that condition represents the unbalanced force condition.

Learn more about the forces here:

brainly.com/question/26115859

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Answer:

Explanation:

Given that;

horizontal circle at a rate of 2.33 revolutions per second

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the baton is 60.1 cm in length.

the magnetic field  is oriented at 14.42°

we wil get the area due to rotation of radius of baton is

\Delta A = \frac{1}{2} \Delta \theta R^2

The  formula for the induced emf is

E = \frac{\Delta  \phi}{\Delta  t}

\phi  = \texttt {magnetic flux}

E=\frac{\Delta (BA) }{\Delta  t}

=B\frac{\Delta  A}{\Delta  t}

B is the magnetic field strength

substitute

\texttt {substitute}\  \frac{1}{2} \Delta \theta R^2 \ \ for \Delta  A

E=B\frac{(\Delta  \theta R^3/2)}{\Delta  t} \\\\=\frac{1}{2} BR^2\omega

The magnetic field of the earth is oriented at 14.42

\omega =2.33\\\\L=60.1c,\\\\\theta=14.42\\\\B=0.5

we plug in the values in the equation above

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E=\frac{1}{2} \times (B\sin \theta)R^2\omega\\\\E=\frac{1}{2} \times (B\sin \theta)(\frac{L}{2} )\omega

=\frac{1}{2} \times0.5gauss\times\frac{0.0001T}{1gauss} \times\sin 14.42\times(\frac{60.1\times10^-^2m}{2} )^2(2.33rev/s)(\frac{2\pi rad}{1rev} )\\\\=2.5\times10^-^5\times0.2490\times0.0903\times14.63982\\\\=2.5\times10^-^5\times0.32917\\\\=8.229\times10^-^6V

6 0
3 years ago
When Woods hits a 0.04593 kg golf ball, the golf ball is usually traveling around 281 kilometers per hour. What average force do
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Answer:

128.9 N

Explanation:

The force exerted on the golf ball is equal to the rate of change of momentum of the ball, so we can write:

F=\frac{\Delta p}{\Delta t}

where

F is the force

\Delta p is the change in momentum

\Delta t=0.030 s is the time interval

The change in momentum can be written as

\Delta p = m(v-u)

where

m = 0.04593 kg is the mass of the ball

u = 0 is the initial velocity of the ball

v=281 km/h =78.1 m/s is the final velocity of the ball

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F=\frac{m(v-u)}{\Delta t}=\frac{(0.04593)(78.1-0)}{0.030}=128.9 N

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Answer:..

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