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Greeley [361]
3 years ago
13

When an object moves, stops moving, changes speed, or changes direction, how do scientists describe that condition? Question 1 o

ptions: a balanced set of forces unbalanced forces frictional force stable factors.
Physics
1 answer:
Dominik [7]3 years ago
4 0

If an object moves, stops, changes speed, or even changes direction, then that condition represents the unbalanced force condition.

Unbalanced Force:

The unbalanced force is the magnitude of the net force that tends to cause the motion of objects. It is nothing but the greater amount of force to be applied to the object to displace the object in either direction.

If an object is moving, stopping, changing the speed, or changing the direction, then such activities directly show that the object is changing its state of motion. And the change in the motion is only caused when there is some magnitude of force associated with it.

  • When the magnitude of forces applied on an object such that one force is greater than another in a specific direction, then such forces are known as unbalanced forces.
  • Unbalanced forces cause motion, which means a body can move, stop or even can change its direction due to the unbalanced force.

Thus, we can conclude that if an object moves, stops, changes speed, or even changes direction, then that condition represents the unbalanced force condition.

Learn more about the forces here:

brainly.com/question/26115859

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1.) the objects have the same temperature

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3 years ago
El coeficiente de variación de la resistencia con la temperatura del carbón es -0.0005/°c.Si la resistencia de una resistencia d
Doss [256]

Answer:

 R (120) = 940Ω

Explanation:

The variation in resistance with temperature is linear in metals

           ΔR (T) = R₀ α ΔT

where α is the coefficient of variation of resistance with temperature, in this case α = -0,0005 / ºC

let's calculate

            ΔR = 1000 (-0,0005) (120-0)

            ΔR = -60 Ω

            ΔR = R (120) + R (0) = -60

            R (120) = -60 + R (0)

            R (120) = -60 + 1000

            R (120) = 940Ω

3 0
3 years ago
A 3.35 kg object initially moving in the positive x direction with a velocity of 4.90 m s collides with and sticks to a 1.88 kg
ahrayia [7]

Answer:

The final components of velocity of the composite object is 3.33 m/s.

Explanation:

Given;

mass of the first object, m₁ = 3.35 kg

initial velocity of the first object, u₁ = 4.90 m/s in positive x-direction

mass of the second object, m₂ = 1.88 kg

initial velocity of the second object, u₂ = 3.12 m/s in negative y-direction

initial momentum of the first object, P₁ = 3.35 x 4.9 = 16.415 kgm/s

initial momentum of the second object, P₂ = 1.88 x 3.12 = 5.8656 kgm/s

The resultant velocity of the two objects is given by;

R² = 16.415² + 5.8656²

R² = 303.858

R = √303.858

R = 17.432 kgm/s

Apply the principle of conservation of linear momentum for inelastic collision;

total initial momentum before = total final momentum after collision

P₁(x) + P₂(y) = Pf

R = Pf

R = v(m₁ + m₂)

17.432 = v(m₁ + m₂)

where;

v is the final components of velocity of the composite object

v = \frac{17.432}{m_1 + m_2} \\\\v = \frac{17.432}{3.35+1.88} \\\\v = 3.33 \ m/s

Therefore, the final components of velocity of the composite object is 3.33 m/s.

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