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Sergeu [11.5K]
4 years ago
15

"You are gowning using the closed cuff method. With the assistance of the circulator, you slid your arms into the gown sleeves t

he full distance they should go. Where should your fingertips be now in relation to the gown cuff?"
Physics
1 answer:
Nastasia [14]4 years ago
4 0

Answer:

The fingertips should be at point of attachment of the cuff to the sleeve

Explanation:

In the closed cuff method, the gown is picked up from the wrapper by holding onto the exposed inside top layer.

The picked up gown should be handled by holding the region close to the neck of the gown, at the same time avoiding contact of the gown with your body or other objects that are unsterile

The arms are then slid into the gown sleeves with the hands at the shoulder level to avoid contact with the body of the gown

The arms are then further slid into the sleeves with the assistance of the circulator to the point where your fingertips are at the midpoint of the attachment of cuff and sleeve

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All objects in our solar system orbit the Sun. How is the movement of planets like
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Two coherent sources of radio waves, A and B, are 5.00 meters apart. Each source emits waves with wavelength 6.00 meters. Consid
Korolek [52]

Answer:

a

    z= 2.5 \ m

b

   z =  (1 \ m ,  4 \ m )

Explanation:

From the question we are told that

     Their distance apart is  d =  5.00 \ m

      The  wavelength of each source wave \lambda =  6.0 \ m

Let the distance from source A  where the construct interference occurred be z

Generally the path difference for constructive interference is

              z - (d-z) =  m \lambda

Now given that we are considering just the straight line (i.e  points along the line connecting the two sources ) then the order of the maxima m =  0

  so

        z - (5-z) =  0

=>     2 z - 5 =  0

=>     z= 2.5 \ m

Generally the path difference for destructive  interference is

           |z-(d-z)| = (2m + 1)\frac{\lambda}{2}

=>         |2z - d |= (0 + 1)\frac{\lambda}{2}

=>        |2z - d| =\frac{\lambda}{2}

substituting values

          |2z - 5| =\frac{6}{2}

=>      z  =  \frac{5 \pm 3}{2}

So  

      z =  \frac{5 + 3}{2}

      z =  4\ m

and

      z =  \frac{ 5 -3 }{2}

=>   z =  1 \ m

=>    z =  (1 \ m ,  4 \ m )

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3 years ago
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