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AURORKA [14]
2 years ago
12

What happens to an object's gravitational potential energy as it falls from some height?​

Physics
1 answer:
saveliy_v [14]2 years ago
3 0

Answer:

Decreases

Explanation:

As an object falls from some height, the gravitational potential energy of the object decreases.

Potential energy is the energy due to the position of a body.

The potential energy is mathematically expressed as:

   Potential energy  = mass x acceleration due to gravity x height

So, potential energy is directly proportional to mass and height.

The higher the mass and height, the more the potential energy.

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A parallel-plate capacitor in air has circular plates of radius 2.8 cm separated by 1.1 mm. Charge is flowing onto the upper pla
Hatshy [7]

Answer:

The time rate of change of the electric field between the plates is  \frac{E }{t} =  2.29 *10^{14} \   N \cdot C  \cdot  s^{-1}  

Explanation:

From the question we are told that

    The  radius is  r =  2.8 \ cm  =  0.028 \ m

     The distance of separation is  d =  1.1  \ mm  =  0.0011 \ m

      The  current is  I  =  5 \ A

Generally the electric field generated is mathematically represented as

         E = \frac{q }{ \pi  *  r^2  \epsilon_o  }

Where \epsilon_o is the permitivity of free space with a value

          \epsilon_o  =  8.85*10^{-12 }\   m^{-3} \cdot kg^{-1}\cdot  s^4 \cdot A^2

So the time rate of change of the electric field between the plates is mathematically represented as

        \frac{E }{t} =   \frac{q}{t} *   \frac{1 }{ \pi  *  r^2  \epsilon_o  }

But \frac{q}{t }  =  I

So  

       \frac{E }{t} =   *   \frac{I }{ \pi  *  r^2  \epsilon_o  }

substituting values  

        \frac{E }{t} =   *   \frac{5 }{3.142  *  (0.028)^2 *   8.85 *10^{-12}  }

        \frac{E }{t} =  2.29 *10^{14} \   N \cdot C  \cdot  s^{-1}

5 0
3 years ago
A heat engine operating at steady state delivers a power output of 15.5 hp. The engine receives energy by heat transfer in the a
Anna007 [38]

Answer:

w_cycle = 13.68 KJ / cycle

Explanation:

Given:

- Steady power out-put W_out = 15.5 hp

- System executes 50 cycles/min

Find:

Determine the amount of work that is delivered during each cycle in kilo-joules

Solution:

- First we will convert the steady output into KW as follows:

                                 W_out = 15.5 hp

The conversion factor is 1.36 KW per hp.

                                 W_out = 15.5 [hp] * [KW] / 1.36 [hp]

                                 W_out = 11.4 [KW] or [KJ/s]

- Given that there are 50 cycles in 60 sec. We will use direct proportionality to calculate the number of cycles per second:

                       50 cycles   -----------> 60 s

                          x cycles   -----------> 1 s

                                 x = 50/60 = 0.8333 cycles /s

- Next we will compute the amount of work done per cycle:

                                 w_cycle = W_out / x

                                 w_cycle = 11.4 [KJ/s] * [s] / 0.8333 [cycles]

                                 w_cycle = 13.68 KJ / cycle

7 0
2 years ago
Desde una altura de 120 m se deja caer un cuerpo. Calcular a los 2,5 s i) la rapidez que lleva; ii) cuánto ha descendido; iii) c
shtirl [24]

Responder: A.) 24.5m / s B.) 30.625m C.) 89.375m

Explicación:

Dado lo siguiente:

Altura desde la cual se cae el cuerpo = 120 m

Tiempo (t) = 2.5s

A.) La velocidad que toma:

El cuerpo cayó desde una altura;

velocidad inicial (u) = 0

Para calcular v:

V = u + en

Donde a = aceleración debido a la gravedad = 9.8m / s

v = 0 + (9.8) (2.5)

v = 24.5 m / s

B) Cuánto ha disminuido.

Usando la ecuación de movimiento:

S = ut + 0.5at ^ 2

Donde S = distancia

S = 0 × 2.5 + 0.5 (9.8) (2.5 ^ 2)

S = 0 + 0.5 (9.8) (6.25)

S = 30.625 m

Esta es la distancia recorrida después de 2.5 segundos Altura o distancia ha disminuido en 30.625 m

C.) ¿CUÁNTO FALTA? Por lo tanto, 120m - 30.625m = 89.375m

5 0
3 years ago
2. Two spherical objects with radii 1 m have masses of 1.5 kg and 8.5 kg. They are separated by a
____ [38]

Answer:

They are separated by a distance of 18 m. Find the gravitational attraction between them. r= 1 m r= 1 m 18 m. Mass = 1.5 kg. Mass = 8.5 kg.

6 0
2 years ago
Which of these statements are true?
Juliette [100K]
D.Neither High- nor low-pressure systems lead to rain
8 0
2 years ago
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