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Alexxx [7]
3 years ago
8

Question number 7, how to calculate the equivalent resistance of the combination of resistors.

Physics
1 answer:
worty [1.4K]3 years ago
5 0

-- On the upper path, the 3 and the 4 are in series, so they look like 7 ohms.

-- On the lower path, the 5 and the 6 are in series, so they look like 11 ohms.

-- Now you have 7 ohms in parallel with 11 ohms. Can you do that ?

It's 4.28 ohms.

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You are pushing a wooden crate across the floor at constant speed. You decide to turn the crate on end, reducing by half the sur
borishaifa [10]

Answer:

D. Half as great

Explanation:

Since we know that the friction force between the surface of crate and ground is given as

F_f = \mu F_n

so here we know that

\mu = friction coefficient between two surfaces which depends on the effective contact area between two surfaces

F_n = normal force due to the object

So when we turn the object on another side such that the surface area is half then the friction coefficient will become also half

So here the friction force will also reduce to half

so correct answer will be

D. Half as great

3 0
3 years ago
Calculate the amount of heat needed to convert 0.8 kg of ice at -19 °C into water at 29 °C.
balu736 [363]
I’m not sure maybe attach a image or something
4 0
3 years ago
Read 2 more answers
The force F acting on a particle constrained to move along the x - axis is given by the fucntion F ( x ) = a x ( b − c x 2 ) [ a
arlik [135]

Answer:

The equilibrium points include

x₁ = - 1.177

x₂ = 0

x₃ = 1.177

Explanation:

At equilibrium, the sum of forces acting on a body is equal to zero.

F(x) = ax (b − cx²) [a = 8.97, b = 7.83, c = 5.65]

F(x) = (abx - acx³)

= (8.97×7.83)x - (8.97×5.65)x³

F(x) = 70.2351x - 50.6805x³

At equilibrium, F(x) = 0

70.2351x - 50.6805x³ = 0

x(70.2351 - 50.6805x²) = 0

x = 0 or (70.2351 - 50.6805x²) = 0

70.2351 - 50.6805x² = 0

50.6805x² = 70.2351

x² = (70.2351/50.6805)

x² = 1.385840708

x = ± 1.177

So, x = -1.177, 0 and 1.177

x₁ = - 1.177

x₂ = 0

x₃ = 1.177

Hope this Helps!!!

6 0
3 years ago
Read 2 more answers
Which of the following statements is true about the variation of pressure in function of the depth? O Pressure decreases exponen
mrs_skeptik [129]

Answer:

The answer is: Pressure increases linearly with the depth

Explanation:

In this case, the definition of pressure is:

P = \frac{F}{A}

where F = mg is the weight of the fluid over the body, and A is the area of the surface to which the force is exerted. If we consider \rho = m/V, then

P = \frac{mg}{A} = \frac{\rho Vg}{A}.

Volume can be expressed as V = A*h, where A is the cross section of the column of the fluid over the body and h is the height of the column, in other words, the depth.

So

P = \frac{A\rho gh}{A}= \rho g h,

which means that pressure increases linearly with the depth in a factor of \rho g.

5 0
3 years ago
two cars collide with each other, before the collision one car ( m=1000 kg) is going north at 20m/s and the other car (m=1200 kg
kow [346]

Answer:

Momentum of system after collision, p = 10,000 kg-m/s                

Explanation:

It is given that,

Mass of car one, m₁ = 1000 kg

Mass of second car, m₂ = 1200 kg

The first car is going towards north and second car is going towards south.

Velocity of car one, v₁ = +20 m/s (towards north)

Velocity of second car, v₂ = - 25 m/s (towards south)

As the momentum remains conserved. So, initial momentum is equal to the final momentum. So,

p_i=p_f=m_1v_1+m_2v_2

p_f=1000\times 20+1200\times (-25)

p_f=-10,000\ kg-m/s

Hence, after collision the momentum of the system will be 10,000 kg-m/s

7 0
3 years ago
Read 2 more answers
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