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Tomtit [17]
2 years ago
12

The summit of mount Everest is at 29,029 feet. At this elevation the atmosphere pressure is 30 kPa or about 0.30 atm. What is th

e boiling point of water at the top of mount Everest
Chemistry
1 answer:
yKpoI14uk [10]2 years ago
5 0

The boiling point of water is 341.74K

Data Given;

  • height = 29,029 ft
  • pressure(p) = 30kpa = 0.30atm
  • T1 = 100^oC or 373K
  • H(vap) = 43653 kJ/mol

The formula to solve this problem is

ln(\frac{1}{p}) = \delta H/R (\frac{1}{T_1} - \frac{1}{T2})

We can solve for the final temperature here;

In(1/0.3) = 40653/8.314(\frac{1}{373}-\frac{1}{T_2})

ln(3.33) = \frac{4809.47}{T_2} - 13.108\\
T_2 = 341.72K = 69^0C

solving for the boiling point of water (T2) at the top,

T2 = 341.72K = 69°C

Learn more about boiling point here;

brainly.com/question/25799467

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