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8090 [49]
2 years ago
12

Texting: what are two needs or wants that this wave technology meets it:

Physics
1 answer:
qaws [65]2 years ago
3 0

Answer:

bugs/viruses all the time and more social platforms

Explanation:

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A crate is pushed up a ramp at an angle of 30 degree by a 300 N force. How much power is spent in raising the crate to a height
kotegsom [21]

Answer:

You use a force of 150 N to push a 30 kg crate across the floor for a distance of 10 m. If the crate is moving at a speed of 5 m/s…

7 0
3 years ago
Explain Why a flying aeroplane has more Kinetic Energy than a flying insect?
Airida [17]

Answer:

Why do insects fly so high?

Because the angle of attack is so high, a lot of momentum is transferred downward into the flow. These two features create a large amount of lift force as well as some additional drag. The important feature, however, is the lift.

Why an Aeroplane flying has kinetic  

A flying aeroplane has potential energy has it flies above the ground level. And since the aeroplane is flying motion is associated with it and thus possesses kinetic energy. Hence a flying aeroplane has both potential and kinetic energ

Explanation:

5 0
3 years ago
Which equation could not be used to determine straight line acceration?
uranmaximum [27]

Answer:

the answer for the question is the last option

5 0
3 years ago
A crate of eggs is located in the middle of the flatbed of a pickup truck as the truck negotiates a curve in the flat road. The
oksian1 [2.3K]

Answer:

v = 14.35 m/s

Explanation:

As we know that crate is placed on rough bed

so here when pickup will take a turn around a circle then in that case the friction force on the crate will provide the necessary centripetal force on the crate

So here we have

\mu mg = \frac{mv^2}{R}

here we have

\mu g = \frac{v^2}{R}

now we know that

v = \sqrt{\mu Rg}

here we have

\mu = 0.600

R = 35 m

g = 9.81 m/s/s

now plug in all values in above equation

v = \sqrt{(0.600)(35)(9.81)}

v = 14.35 m/s

4 0
3 years ago
A toy rocket is launched with an initial velocity of 10.0 m/s in the horizontal direction from the roof of a 38.0-m-tall buildin
Bas_tet [7]

Answer:

Explanation:

Consider downward displacement first .

downward displacement h = 38 m .

downward acceleration = g

downward initial velocity u = 0

h = ut + 1/2 g t ²

38 = 0 + 9.8 t ²

t = 1.97 s

During this period , there will be horizontal displacement with initial velocity u = 10 m /s and acceleration a = 1.6 m /s²

s = ut + 1/2 a t²

= 10 x 1.97 + .5 x 1.6 x 1.97²

= 19.7 + 3.10

= 22.8 m

3 0
3 years ago
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