Answer:
The magnitude of the EMF is 0.00055 volts
Explanation:
The induced EMF is proportional to the change in magnetic flux based on Faraday's law:
![emf\,=-\,N\, \frac{d\Phi}{dt}](https://tex.z-dn.net/?f=emf%5C%2C%3D-%5C%2CN%5C%2C%20%5Cfrac%7Bd%5CPhi%7D%7Bdt%7D)
Since in our case there is only one loop of wire, then N=1 and we get:
![emf\,=-\,N\, \frac{d\Phi}{dt}](https://tex.z-dn.net/?f=emf%5C%2C%3D-%5C%2CN%5C%2C%20%5Cfrac%7Bd%5CPhi%7D%7Bdt%7D)
We need to express the magnetic flux given the geometry of the problem;
where A is the area of the coil that remains unchanged with time, and B is the magnetic field that does change with time. Therefore the equation for the EMF becomes:
![emf\,=-\,N\, \frac{d\Phi}{dt} = \frac{d\Phi}{dt} =-\frac{d\,(B\,A)}{dt} =-\,A\,\frac{d\,(B)}{dt}=- 1\,m^2(2\,\,T/h})= -2\,\,m^2\,T/(3600\,\,s)= -0.00055\,Volts](https://tex.z-dn.net/?f=emf%5C%2C%3D-%5C%2CN%5C%2C%20%5Cfrac%7Bd%5CPhi%7D%7Bdt%7D%20%3D%20%5Cfrac%7Bd%5CPhi%7D%7Bdt%7D%20%3D-%5Cfrac%7Bd%5C%2C%28B%5C%2CA%29%7D%7Bdt%7D%20%3D-%5C%2CA%5C%2C%5Cfrac%7Bd%5C%2C%28B%29%7D%7Bdt%7D%3D-%201%5C%2Cm%5E2%282%5C%2C%5C%2CT%2Fh%7D%29%3D%20-2%5C%2C%5C%2Cm%5E2%5C%2CT%2F%283600%5C%2C%5C%2Cs%29%3D%20-0.00055%5C%2CVolts)
Answer:
elliptical orbit
Explanation:
There are three laws of planetary motion, which are called Kepler's law of planetary motion.
First Law : It states that all the planets revolve around the sun in an elliptical path and the sun is at one focus of that elliptical path.