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konstantin123 [22]
2 years ago
5

Describe how you could made a sound wave have a higher pitch.

Physics
1 answer:
77julia77 [94]2 years ago
7 0
In order to make a sound wave have a higher pitch you increase the frequency.
In order to increase the volume of a sound wave, you have to increase the amplitude. Hope this helps!
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What minimum volume must the slab have for a 75.0 kgkg woman to be able to stand on it without getting her feet wet
Alisiya [41]

V = 0.9375 m3 is minimum volume .

<h3>What is density ?</h3>
  • We use the word "density" to indicate how much space (or "volume") an object or substance occupies in relation to the amount of matter contained therein (its mass).
  • Density can also be defined as the quantity of mass per unit of volume. A dense object is one that is both hefty and small.

Given,

            1000 kg/m3 = density of water

             920 kg/m3 = density of ice

BF = Woman Weight + Slab Weight

Pvg = 75 + Pvg

V = 75 kg / (1000 - 920)

V = 75 / 80

V = 0.9375 m3

Therefore, V = 0.9375 m3 is minimum volume .

Learn more about density

brainly.com/question/952755

#SPJ4

6 0
2 years ago
A 0.0427 kg racquet-ball is moving
Gwar [14]

Answer:

Mass of the box = 0.9433 kg

Explanation:

Mass of racket-ball (m_1) = 0.00427 kg

Velocity of racket-ball before collision (v_{1i}) = 22.3 m/s

Velocity of racket-ball after collision with box (v_{1f}) = -11.5 m/s

[Since ball is bouncing back, so velocity is taken negative.]

Velocity of the box before collision v_{2i} = 0 m/s

<em>[Since the box is stationary, so velocity is taken zero]</em>

Velocity of box moving forward after collision v_{2f}= 1.53 m/s

To find the mas of the box m_2.

By law of conservation of momentum we have:

Momentum before collision = Momentum after collision

This can be written as:

p_i=p_f

m_1v_{1i}+m_2v_{2i}=m_1v_{1f}+m_2v_{2f}

We can plugin the given value to find m_2

(0.0427\times 22.3)+(m_2\times 0)=(0.0427\times (-11.5))(m_2\times 1.53)

0.9522+0=-0.4911+1.53m_2

Adding both sides by 0.4911

0.9522+0.4911=-0.4911+0.4911+1.53m_2

1.4433=1.53m_2

Dividing both sides by 1.53.

\frac{1.4433}{1.53}=\frac{1.53m_2}{1.53}

0.9433=m_2

∴ m_2=0.9433 kg

Mass of the box = 0.9433 kg (Answer)

4 0
3 years ago
Please help me I have to send for my teacher​
expeople1 [14]

Answer:

for the fill in the blanks

1- static

2-kinetic

3-coeffiecient

4-opposite to

5-sin theta

6-cos theta

im not sure however what to do with the top part or if its even part of what you need help with

8 0
2 years ago
A toy doll and a toy robot are standing on a frictionless surface facing each other. The doll has a mass of 0.2 kg, and the robo
Natali5045456 [20]

Answer:

<h3>1.43m/s²</h3>

Explanation:

According to newtons second law.

F = mass * acceleration

If the doll has a mass of 0.2 kg, and the robot has a mass of 0.5 kg, the resulting mass will be 0.7kg

Force applied = 1N

acceleration = Force/mass

Substitute the values and get acceleration

acceleration = 1/0.7

acceleration = 1.43m/s²

Hence the magnitude of the acceleration of the robot is 1.43m/s²

3 0
2 years ago
The OBD-II catalytic converter monitor uses _______ sensor(s) to monitor catalytic converter efficiency.
oksano4ka [1.4K]
C comment for an explanation
8 0
3 years ago
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