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mina [271]
4 years ago
10

A force acting on an object does no work if _____.

Physics
1 answer:
quester [9]4 years ago
4 0
The force is greater than the force of friction is your answer but i would double check cuz im not 110% sure
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SONAR stands for "sound navigation and ranging,” and it is used to map and explore the ocean floor.
lara31 [8.8K]
SONAR stands for "sound navigation and ranging,” and it is used to map and explore the ocean floor.
3 0
3 years ago
A truck covers 40.0 m in 7.10 s while smoothly slowing down to a final velocity of 2.75 m/s.. (a) Find the truck's original spee
ser-zykov [4K]
D = vo t - at²/2
v = vo - at
40 m = vo · 7.10 - a · ( 7.10 )²/2
40 m = 7.10 vo - a· 50.41/2
40 m = 7.10 vo - 25.205 a
2.75 m/s = vo - 7.10 a   ⇒  a = ( vo - 2.75 )/ 7.10
40 = 7.10 vo - 25.205 · ( vo - 2.75 ) / 7.10
40 = 7.1 vo - 3.55 vo + 9.7625
3.55 vo = 30.2375 
vo = 30.2375 : 3.55 = 8.5176 m/s
Answer: the truck`s original speed is 8.5176 m/s.
 
4 0
4 years ago
A tank, shaped like a cone has height 12 meter and base radius 1 meter. It is placed so that the circular part is upward. It is
Temka [501]

Answer:

376966.991 Joules

Explanation:

Given that :

the height = 12  m

Let assume the tank have a thickness  = dh

The radius of the tank by using the concept of similar triangle is :

\dfrac{1}{r} = \dfrac{12}{h}

r = \dfrac{h}{12}

The area of the tank = \mathbf{\pi r^2}

The area of the tank = \mathbf{\pi( \dfrac{h}{12})^2}

The area of the tank = \mathbf{ \dfrac{\pi}{144}h^2}

The volume of the tank is  = area × thickness

= \mathbf{ \dfrac{\pi}{144}h^2 \  dh}

Weight of the element = \rho_ g * volume

where;

\rho_g = density of water ; which is given as 10000 N/m³

So;

Weight of the element = \mathbf{ 10000 *\dfrac{\pi}{144}h^2 \  dh}

Weight of the element = \mathbf{69.44 \ \pi  \ h^2 \  dh}

However; the work required to pump this water = weight × height  rise

where the height rise = 12 - h

the work required to pump this water  = \mathbf{69.44 \ \pi  \ h^2 \  dh}(12 - h)

the work required to pump this water  = \mathbf{69.44 \pi (12h^2-h^3)dh}

We can determine the total workdone by integrating the work required to pump this water

SO;

Workdone = \mathbf{\int\limits^{12}_0 {69.44 \pi(12h^2-h^3)} dh}

= \mathbf{ 69.44 \pi \int\limits^{12}_0 {(12h^2-h^3)} dh}

=  \mathbf{ 69.44 \pi[ \frac{12h^3}{3}-  \frac{h^4}{4}]^{12}}_0} }

= \mathbf{69.44 \pi [ \frac{12^4}{3}-\frac{12^4}{4}]}

= \mathbf{69.44 \pi*12^4 [ \frac{4-3}{12}]}

= \mathbf{69.44 \pi*12^4 *\frac{1}{12}}

= 376966.991 Joules

6 0
3 years ago
How are hypotheses and theories related to each other?
GREYUIT [131]
Hypotheses and theories related to each other since hypotheses are used in creating a theory. Hypotheses are explanations for some phenomenon that are still proposed. When these are validated and proved, they are accepted by the public as theories and are used to explain natural phenomenon.
5 0
4 years ago
A 500-W heating coil designed to operate from 110V is made of Nichrome wire 0.500 mm in diameter. (a) Assuming the resistivity o
Cloud [144]

The length of the wire used is 3.162 m

<h3>Resistivity of a material</h3>

The formula for calculating the power is expressed as;

P = V²/R

Determine th resistance

R =  V²/P

Determine the resistance of the heating coil by substituting

R = (110²/500)

R = 12100/500

R = 24.2ohms

Determine the length of the wire

R = ρL/A such that;

L = RA/ρ

Substitute the given parameters

diameter = 0.5 mm = 0.0005m

radius = 0.0005/2 = 0.00025 m

Determine the area

A = πr²

A = π * 0.00025²

A = 1.96*10^-7 m²

Determine the length

L = (24.2 * 1.96*10^-7 / 1.50*10^-6) =

L = 3.162 m

Hence the length of the wire used is 3.162 m

The length of the wire used is 3.162 m

Learn more on resistivity here; brainly.com/question/24858512

#SPJ4

3 0
1 year ago
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