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VladimirAG [237]

3 years ago

7

Help with Order of Magnitude question?

1 answer:

solong [7]3 years ago

7 0

The rotation of Earth is equivalent to one day which is comprised of 24 hours. To determine the number of miles in Earth's circumference, one simply have to multiply the given rate by the appropriate conversion factor and dimensional analysis. This is shown below.

C = (1038 mi/h)(24 h/1 day)
C = 24,912 miles

From the given choices, the nearest value would have to be 20,000 mile. The answer is the second choice.

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According to Boyle’s law, PV= K, what was the volume at the time of the first measurement given the following information? Round

alexandr402 [8]

Answer:

Iam a learning

6 0

3 years ago

Consider the plot below describing motion along a straight line with an initial position of 10 m. −4 −3 −2 −1 0 1 2 3 4 5 6 1 2

Ugo [173]

Answer:

$+1 m/s^2$

Explanation:

Acceleration is given by

$a=\frac{\Delta v}{\Delta t}$

where

$\Delta v$ is the change in velocity

$\Delta t$ is the time interval in which the change in velocity occurs

To find the acceleration at 1 second, we can take the data at t = 1 s and t = 2. We find:

$\Delta t = -3 -(-4) = 1 s$

$\Delta v = 2 - (1) = +1 m/s$

So, the acceleration is

$a=\frac{+1}{1}=+1 m/s^2$

4 0

3 years ago

The Sun is about 150 million km from earth. how long does it take light from the sun to reach earth? (Speed of light is 3x10^8m/

madam [21]

Time =      (distance) / (speed)

Time = (150 x 10⁹ m) / (3 x 10⁸ m/s) =

   50 x 10¹ sec =

       <em>500 sec</em> = 8 min 20 sec

3 0

4 years ago

A drag racer starts from the rest and accelerates at 7.4m/s^2.how far will he travel in 2.0 seconds?

Vesna [10]

Answer:

14.8 m

Explanation:

S= ut + $\frac{1}{2}$ a $t^{2}$

where u = initial velocity

S= (0 $\frac{m}{s}$ )(2 $s$ ) + $\frac{1}{2}$ (7.4 $\frac{m}{s^{2} }$ )(2 $s^{2}$ )

S= $\frac{1}{2}$ (7.4 $\frac{m}{s^{2} }$ )(2 $s^{2}$ )

S=14.8 m

8 0

3 years ago

If the amplitude of a simple harmonic oscillator is doubled, by what factor does the total energy increase?

dybincka [34]

Answer:

c)by a factor of four

Explanation:

The total energy of a simple harmonic oscillator is given by

$E=\frac{1}{2}kA^2$

where

k is the spring constant of the oscillator

A is the amplitude of the motion

In this problem, the amplitude of the oscillator is doubled, so

A' = 2A

Therefore, the new total energy is

$E'=\frac{1}{2}k(2A)^2=4(\frac{1}{2}kA^2)=4E$

So, the total energy increases by a factor 4.

6 0

3 years ago