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3 years ago

Help with Order of Magnitude question?

1 answer:

7 0

The rotation of Earth is equivalent to one day which is comprised of 24 hours. To determine the number of miles in Earth's circumference, one simply have to multiply the given rate by the appropriate conversion factor and dimensional analysis. This is shown below.

C = (1038 mi/h)(24 h/1 day)
C = 24,912 miles

From the given choices, the nearest value would have to be 20,000 mile. The answer is the second choice.

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Displacement and distance example

andriy [413]

Answer:

Distance is the whole travel from A to B and B to C.

While, displacement is the shortcut directly from A to C.

3 0

4 years ago

A box (250 kg) sits inside the trailer of a semitruck traveling at a speed of 25 m/s (~ 55 mph). Suddenly, a car in front of the

shtirl [24]

Answer:

RIGHT

Explanation:

given,

mass of box = 250 kg

speed of the truck = 25 m/s

static friction µs = 0.7

g = 10 m/s²

to find direction of friction on the box

truck is moving in left direction and suddenly in front of truck a car stops then the driver hit the brake hard so at that moment the box on the trailer will have the tendency to move left so to oppose its movement friction force will be on RIGHT

3 0

3 years ago

Help!!! Line B touches the circle at a single point. Line A extends through the center of the circle.

Ulleksa [173]

Answer:

If I understand correctly. Line B is parallel to the circle. Also, the angle is less than 90.

The size of the circle determines.
The diameter should not be fixed either.

3 0

3 years ago

Why echo sound cannot be heard in small room

Art [367]

They can't hear an echo in small room because in it the sound can't be reflected back. For an echo of a sound to be heard,the minimum distance between the source of sound and the walls of the roomshould be 17.2 m. Obviously,in asmall room echoes cannot beheard.

7 0

3 years ago

A tightly wound 1000-turn toroid has an inner radius 1.00 cm and an outer radius 2.00 cm, and carries a current of 1.50 A. The t

V125BC [204]

Therefore, the magnitude of magnetic field at a distance 1.10cm from the origin is 27.3mT

<u>Explanation:</u>

Given;

Number of turns, N = 1000

Inner radius, r₁ = 1cm

Outer radius, r₂ = 2cm

Current, I = 1.5A

Magnetic field strength, B = ?

The magnetic field inside a tightly wound toroid is given by B = μ₀ NI / 2πr

where,

a < r < b and a and b are the inner and outer radii of the toroid.

The magnetic field of toroid is

$B = \frac{u_oNI}{2\pi r}$

Substituting the values in the formula:

$B (1.10cm) = \frac{(4\pi X 10^-^7 ) ( 1000)(1.5)}{2\pi (1.10) } \\\\$

$B (1.10cm) = 27.3mT$

Therefore, the magnitude of magnetic field at a distance 1.10cm from the origin is 27.3mT

7 0

3 years ago