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sattari [20]
3 years ago
6

Assuming the acceleration due to gravity on the moon is exactly one-sixth of the acceleration due to gravity on Earth, what is t

he weight of the object on the moon?
Physics
1 answer:
uysha [10]3 years ago
5 0

<u>I have assumed a weight of 120 N on Earth.</u>

Answer:

<em>The object weighs 20 N on the moon</em>

Explanation:

Weight

The weight of an object depends on the mass m of the object and the acceleration of gravity g of the place they are in.

The formula to calculate the weight is:

W = m.g

If g_e is the acceleration of gravity on Earth, and g_m is the acceleration of gravity on the moon, we know:

g_m=1/6 g_e

Dividing by ge:

g_m/g_e = 1/6

An object of weight We=120 N on planet Earth has a mass of:

m = 120 / g_e

Multiplying by gm:

m.g_m=120 g_m/g_e

Substituting the ratio of accelerations of gravity:

m.g_m=120 * 1/6

Since m.gm is the weight on the Moon Wm:

W_m=20~N

The object weighs 20 N on the moon

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15 points! An atomic nucleus initially moving at 420 m/s emits an alpha particle in the direction of its velocity, and the remai
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The alpha particle is emitted at 4235 m/s

Explanation:

We can use the law of conservation of momentum to solve the problem: the total momentum of the original nucleus must be equal to the total momentum after the alpha particle has been emitted. Therefore:

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where:  

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v=420 m/s is the initial velocity of the nucleus

m_1 = 4 u is the mass of the alpha particle

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Solving for v_1, we  find the final velocity of the alpha particle:

v_1 = \frac{Mu-m_2 v_2}{m_1}=\frac{(222)(420)-(218)(350)}{4}=4235 m/s

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4 0
3 years ago
Joey drives along the 110 South freeway and notices a mile marker that reads 260 miles. He drives until he reaches the 150 mile
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Answer:

85 miles .

Explanation:

Displacement along the 110 South freeway = 260 - 150  =  110 miles

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Net displacement = 110 - 25 = 85 miles

So Joey's displacement from the 260 mile marker is 85 miles .

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IV) Fill in the blanks:
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1.) equal volume of different substances have "different" masses.

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I hope this helps you...

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3 years ago
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