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sattari [20]
3 years ago
6

Assuming the acceleration due to gravity on the moon is exactly one-sixth of the acceleration due to gravity on Earth, what is t

he weight of the object on the moon?
Physics
1 answer:
uysha [10]3 years ago
5 0

<u>I have assumed a weight of 120 N on Earth.</u>

Answer:

<em>The object weighs 20 N on the moon</em>

Explanation:

Weight

The weight of an object depends on the mass m of the object and the acceleration of gravity g of the place they are in.

The formula to calculate the weight is:

W = m.g

If g_e is the acceleration of gravity on Earth, and g_m is the acceleration of gravity on the moon, we know:

g_m=1/6 g_e

Dividing by ge:

g_m/g_e = 1/6

An object of weight We=120 N on planet Earth has a mass of:

m = 120 / g_e

Multiplying by gm:

m.g_m=120 g_m/g_e

Substituting the ratio of accelerations of gravity:

m.g_m=120 * 1/6

Since m.gm is the weight on the Moon Wm:

W_m=20~N

The object weighs 20 N on the moon

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monitta

Answer:

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Explanation:

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3 years ago
How are climate and weather related?
iris [78.8K]
Weather is what conditions of the atmosphere are over a short period of time, and climate is how the atmosphere "behaves" over relatively long periods of time.
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3 years ago
The moment of inertia for a 5500 kg solid disc is 12100 kg-m^2. Find the radius of the disc? (a) 2.111 m (b) 2.579 m (c) 1.679
Soloha48 [4]

Answer:

The radius of the disc is 2.098 m.

(e) is correct option.

Explanation:

Given that,

Moment of inertia I = 12100 kg-m²

Mass of disc m = 5500 kg

Moment of inertia :

The moment of inertia is equal to the product of the mass and square of the radius.

The moment of inertia of the disc is given by

I=\dfrac{mr^2}{2}

Where, m = mass of disc

r = radius of the disc

Put the value into the formula

12100=\dfrac{5500\times r^2}{2}

r=\sqrt{\dfrac{12100\times2}{5500}}

r= 2.098\ m

Hence, The radius of the disc is 2.098 m.

8 0
3 years ago
Electromagnetic waves can transfer energy without a(n) _____________ (medium/electric field).
KATRIN_1 [288]
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7 0
3 years ago
A(n) 131 g ball is dropped from a height
larisa [96]

Answer:

26.59 N/m

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 131 g

Extention (e) = 4.82755 cm

Acceleration due to gravity (g) = 9.8 m/s²

Spring constant (K) =?

Next, we shall convert 131 g to Kg. This can be obtained as follow:

1000 g = 1 Kg

Therefore,

131 g = 131 g × 1 Kg / 1000 g

131 g = 0.131 Kg

Thus, 131 g is equivalent to 0.131 Kg.

Next, we shall the force exerted by the ball on the spring. This can be obtained as follow:

Mass (m) = 0.131 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Force (F) =?

F = ma

F = 0.131 × 9.8

F = 1.2838 N

Next, we shall convert 4.82755 cm to metre (m)

This can be obtained as follow:

100 cm = 1 m

Therefore,

4.82755 cm = 4.82755 cm × 1 m / 100 cm

4.82755 cm = 0.0482755 m

Thus, 4.82755 cm is equivalent to 0.0482755 m

Finally, we shall determine the spring constant as follow:

Force (F) = 1.2838 N

Extention (e) = 0.0482755 m

Spring constant (K) =?

F = Ke

1.2838 = K × 0.0482755

Divide both side by 0.0482755

K = 1.2838 / 0.0482755

K = 26.59 N/m

Thus the spring constant is 26.59 N/m

7 0
3 years ago
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