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sattari [20]
3 years ago
6

Assuming the acceleration due to gravity on the moon is exactly one-sixth of the acceleration due to gravity on Earth, what is t

he weight of the object on the moon?
Physics
1 answer:
uysha [10]3 years ago
5 0

<u>I have assumed a weight of 120 N on Earth.</u>

Answer:

<em>The object weighs 20 N on the moon</em>

Explanation:

Weight

The weight of an object depends on the mass m of the object and the acceleration of gravity g of the place they are in.

The formula to calculate the weight is:

W = m.g

If g_e is the acceleration of gravity on Earth, and g_m is the acceleration of gravity on the moon, we know:

g_m=1/6 g_e

Dividing by ge:

g_m/g_e = 1/6

An object of weight We=120 N on planet Earth has a mass of:

m = 120 / g_e

Multiplying by gm:

m.g_m=120 g_m/g_e

Substituting the ratio of accelerations of gravity:

m.g_m=120 * 1/6

Since m.gm is the weight on the Moon Wm:

W_m=20~N

The object weighs 20 N on the moon

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A rocket lifts off the pad at cape canaveral. according to newton's law of gravitation, the force of gravity on the rocket is gi
Alenkinab [10]
The equation is the Law of Universal Gravitation. The gravitational constant G is equal to 6.67×10⁻¹¹ Nm²/kg². The mass of the Earth is <span>5.972 ×10</span>²⁴ kg. Compared to the mass of the Earth, the mass of the rocket is negligible. So, we don't need to know the mass of the rocket. Substituting the values:

F = (6.67×10⁻¹¹ Nm²/kg²)(5.972 ×10²⁴ kg)/(4000 miles*(1.609 km/1mile))²
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8 0
4 years ago
Were there experiences in his life that led to his interest in science and the study of the atom?
charle [14.2K]

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Explanation:

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5 0
2 years ago
Read 2 more answers
If a sound wave is produced by a speaker at room temperature and has a
Oksana_A [137]

Answer: 183.8Hz

Explanation:

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wavelength of sound (λ) = 1.85 m

frequency of the sound (F) = ?

Recall that the speed of sound (V) in air is a constant with a value of 340m/s

So, apply the formula

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340 m/s = F x 1.85 m

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3 years ago
Shay reacts solid zinc and aqueous copper sulfate to form aqueous zinc sulfate and solid copper. If he reacts 10.1 grams of zinc
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Answer:

Now since mass of reactant is equal to mass of the product after the reaction so we can say that mass conservation is applicable here

Explanation:

As we know that zinc reacts with copper sulfate

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so here we have

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ZnSO_4 = 20 g

Cu = 8.7 g

Now total mass of reactant is given as

M_1 = 10.1 + 18.6 = 28.7 g

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