Assuming the acceleration due to gravity on the moon is exactly one-sixth of the acceleration due to gravity on Earth, what is t
1 answer:
<u>I have assumed a weight of 120 N on Earth.</u>
Answer:
<em>The object weighs 20 N on the moon</em>
Explanation:
Weight
The weight of an object depends on the mass m of the object and the acceleration of gravity g of the place they are in.
The formula to calculate the weight is:
W = m.g
If g_e is the acceleration of gravity on Earth, and g_m is the acceleration of gravity on the moon, we know:
Dividing by ge:
An object of weight We=120 N on planet Earth has a mass of:
Multiplying by gm:
Substituting the ratio of accelerations of gravity:
Since m.gm is the weight on the Moon Wm:
The object weighs 20 N on the moon
You might be interested in
Hello, love! The answer is True, or T, on Edge2020.
Hope this helped!
~ V.
Answer:
Explanation:
Given
Initial reading on scale =40 N
So, we can conclude that weight of the sack is 40 N
After this a 10 N force is applied upward on the sack such that the net force becomes (40-10) N downward (because downward force is more)
This net downward force is the resultant of earth graviational pull and the applied upward force.
So, this downward force acts on the machine which inturn applies an upaward force of same magnitude called Normal reaction.
This situation can be diagramatically represented by figure given below
Answer:
The vertical distance is
Explanation:
From the question we are told that
The mass of the cylinder is m
The kinetic frictional force is f
Generally from the work energy theorem
Here E the the energy of the spring which is increasing and this is mathematically represented as
Here k is the spring constant
P is the potential energy of the cylinder which is mathematically represented as
And
is the workdone by friction which is mathematically represented as
So
=>
=>
=>