Answer:
-16/13
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(-9-7)/(17-4)
m=-16/13
Answer:
the answer is 1
Step-by-step explanation:
69 goes into 69, 1 time
Answer:
7.5
Step-by-step explanation:
106% of $x = $7.95
In other words,
![\[\frac{106}{100}\]](https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7B106%7D%7B100%7D%5C%5D)
of $x = 7.95
Multiplying both sides of the equation by ![\[\frac{100}{106}\]](https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7B100%7D%7B106%7D%5C%5D)
![\[\frac{106}{100} * \frac{100}{106}\]](https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7B106%7D%7B100%7D%20%2A%20%5Cfrac%7B100%7D%7B106%7D%5C%5D)
of x = 7.95 * ![[\frac{100}{106}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B100%7D%7B106%7D%5D)
=> x = ![[\frac{750}{100}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B750%7D%7B100%7D%5D)
=> x = ![[\frac{7.50}{1}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B7.50%7D%7B1%7D%5D)
=> x = 7.5
Validation: 106% of 7.5 = 7.95
Answer:
We accept H₀ we don´t have enough evidence to support that the mean thickness is greater than 41 mm
Step-by-step explanation:
Sample Information:
Results:
41.8
40.9
42.1
41.2
40.5
41.1
42.6
40.6
From the table we get:
sample mean : x = 41.35
sample standard deviation s = 0.698
Hypothesis Test:
Null Hypothesis H₀ x = 41
Alternative Hypothesis Hₐ x > 41
The test is a one-tail test
If significance level is 0.01 and n = 8 we need to use t-student distribution
From t-table α = 0.01 and degree of freedom df = n - 1 df = 8 - 1
df = 7 t(c) = 2.998
To calculate t(s) = ( x - 41 ) / s/√n
t(s) = ( 41.35 - 41 ) / 0.698/√8
t(s) = 0.35 * 2.83/ 0.698
t(s) = 1.419
Comparing t(s) and t(c)
t(s) < t(c)
t(s) is in the acceptance region we accept H₀
Answer:
(x + 3b)(3 + 5a)
Step-by-step explanation:
Assuming you require the expression factorised.
Given
3x + 9b + 5ax + 15ab ( factor the first/second and third/fourth terms )
= 3(x + 3b) + 5a(x + 3b) ← factor out (x + 3b) from each term
= (x + 3b)(3 + 5a) ← in factored form
