Answer:
12 divided by 12 is 1
Step-by-step explanation:
A calculator helped me
Answer:
75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.
Step-by-step explanation:
The question is missing. It is as follows:
Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69 104 125 129 60 64
Assume that the population of x values has an approximately normal distribution.
Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)
75% Confidence Interval can be calculated using M±ME where
- M is the sample mean weight of the wild mountain lions (
)
- ME is the margin of error of the mean
And margin of error (ME) of the mean can be calculated using the formula
ME=
where
- t is the corresponding statistic in the 75% confidence level and 5 degrees of freedom (1.30)
- s is the standard deviation of the sample(31.4)
Thus, ME=
≈16.66
Then 75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5
Answer:
A. -4/11
Step-by-step explanation:
Slope formula: 
Using the two points substitute the coordinates into this formula
6-2 = 4
4 - 7 = -11
Put 4 over -11 because it is the y value

Given:
Line A: 2x + 2y = 8
Line B: x + y = 4
x = 4 - y
2(4-y) + 2y = 8
8 - 2y + 2y = 0
0 = -8
y = 4 - x
2x + 2(4-x) = 8
2x + 8 - 2x = 8
0 = 0
There is no solution.
Answer:B
Step-by-step explanation: Alternate exterior angles theorem