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Vikentia [17]
2 years ago
10

Jack jogs and rides his bike for a total of 75 minutes every day. He rides his bike for 15 minutes longer than he jogs. Part A:

Write a pair of linear equations to show the relationship between the number of minutes Jack jogs (x) and the number of minutes he rides his bike (y) every day. (5 points).
Mathematics
2 answers:
ivolga24 [154]2 years ago
6 0

Jack jogs for 30 minutes and he rides his bike for 45 minutes

Let x represent the number of minutes jogged and y represent the number of minutes that he ride his bike.

Jack jogs and rides his bike for a total of 75 minutes every day. hence:

x + y = 75   (1)

He rides his bike for 15 minutes longer than he jogs. hence:

y = x + 15

-x + y = 15    (2)

Solving equations 1 and 2 simultaneously gives:

x = 30, y = 45

Jack jogs for 30 minutes and he rides his bike for 45 minutes

Find out more on equation at: brainly.com/question/13763238

HACTEHA [7]2 years ago
3 0

Answer:

for B : he spend 30 minutes jogging and 45 minutes riding his bike

Step-by-step explanation:

75-15=60

60/2=30

jogging (x) =30

30+15=45

riding bike (y) =45

hopefully that help with B

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What is the cross-sectional area of a cement pipe 2 in. thick with an inner diameter of 5 ft? Use pie 3.14.
Paul [167]

Answer:

1.60 ft^{2}

Step-by-step explanation:

Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.

i.e Area = \pir^{2}

So that,

for the inner part of the pipe,

r = \frac{diameter}{2}

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Area of the inner part of the pipe = \pir^{2}

                                 = 3.14 x (2.5)^{2}

                                 = 19.625

Are of the inner part of the pipe is 19.63 ft^{2}.

Total diameter of the pipe = 5 + 0.2

                                           = 5.2 feet

r = \frac{5.2}{2}

 = 2.6 feet

Area of the pipe = \pir^{2}

                            = 3.14 x (2.6)^{2}

                            = 21.2264

Area of the pipe is 21.23 ft^{2}.

Thus the cross sectional area = Area of the pipe - Area of the inner part of the pipe

                                           = 21.2264 - 19.625

                                           = 1.6014

The cross sectional area of the cement pipe is 1.60 ft^{2}.

6 0
2 years ago
See comment for what I need
Roman55 [17]

Answer:

I already sent u the link from there, even tho, they deleted my question, but yh i set the title as well incase u needed it! Good luck

Step-by-step explanation:

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Ok so I will give the person who answers all of these problems correctly 60 points
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