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3 years ago

Determine the factors of 5x2 + 29x _ 6

Mathematics

2 answers:

Eduardwww [97]3 years ago

7 0

Answer:

The factors of given equation $5x^2+29x-6$ is $(5x-1)(x+6)$

Step-by-step explanation:

Given equation $5x^2+29x-6$

We have to determine the factors of given equation.

Quadratic equation is an equation with highest degree 2.

Consider the given quadratic equation $5x^2+29x-6$

We can solve the quadratic equation $5x^2+29x-6$ using middle term splitting method.

splitting middle term can be done by writing middle term in such a way that the product of coefficient is the product of remaining two terms.

29x can be written as 30x-1x

$\Rightarrow 5x^2+29x-6$

$\Rightarrow 5x^2+30x-x-6$

Taking 5x common from first two terms and -1 from last two terms , we have,

$\Rightarrow 5x(x+6)-1(x+6)$

$5x^2+29x-6=(5x-1)(x+6)$

Thus, the factors of given equation $5x^2+29x-6$ is $(5x-1)(x+6)$

Andre45 [30]3 years ago

6 0

The answer is (x + 6)(5x - 1).

5x² + 29x - 6 = 5x² + 30x - x - 6 =
= (5x · x + 5x · 6) - (x + 6) =
= 5x(x + 6) - 1(x + 6) =
= (x + 6)(5x - 1)

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Alex73 [517]

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Triangle DEF (not shown) is similar to ABC shown, with angle B congruent to angle E and angle C congruent to angle F. The length

Bezzdna [24]

Answer:

Area of ΔDEF is $45\ cm^2$ .

Step-by-step explanation:

Given;

ΔABC and ΔDEF is similar and ∠B ≅ ∠E.

Length of AB = $2\ cm$ and

Length of DE = $6\ cm$

Area of ΔABC = $5\ cm^2$

Solution,

Since, ΔABC and ΔDEF is similar and ∠B ≅ ∠E.

Therefore,

$\frac{Area\ of\ triangle\ 1}{Area\ of\ triangle\ 2} =\frac{AB^2}{DE^2}$

Where triangle 1 and triangle 2 is ΔABC and ΔDEF respectively.

If two triangles are similar, then the ratio of the area of both triangles is proportional to the square of the ratio of their corresponding sides.

$\frac{5}{Area\ of\ triangle\ 2} =\frac{2^2}{6^2}\\ \frac{5}{Area\ of\ triangle\ 2}=\frac{4}{36}\\ Area\ of\ triangle\ 2=\frac{5\times36}{4} =5\times9=45\ cm^2$