Mass = moles x Mr
So in this case the moles =1
And the Mr equals =11
So you would do - 11x1= 11grams
Boyle's law gives the relationship between pressure and volume of gases.
it states that for a fixed amount of gas at constant temperature, pressure of gas is inversely proportional to volume.
PV = k
where P - pressure , V - volume and k - constant
P1V1 = P2V2
where parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
substituting this equation
P x 0.5650 L = 715.1 bar x 1.204 L
P = 1 524 bar
Answer:
The molecular weight for the compound is 60.1 g/mol
Explanation:
We need to determine the molality of solute to find out the molar mass of it.
We apply the colligative property of freezing point depression:
ΔT = Kf . m . i
If the compound was also found to be nonvolatile and a non-electrolyte,
i = 1.
Freezing T° of pure solvent - Freezing T° of solution = Kf . m
0°C - (-2.05°C) = 1.86°C/m . m
2.05°C / 1.86m/°C = m → 1.10 mol/kg
To determine the moles of solute we used, we can multiply molality by the mass of solvent in kg → 202.1 g . 1kg/1000g = 0.2021 kg
1.10 mol/kg . 0.2021kg = 0.223 moles
Molar mass→ g/mol → 13.39 g / 0.223 mol = 60.1 g/mol
Answer:
THE INITIAL VOLUME OF THE STOCK SOLUTION IS 0.0392 L OR 39.2 mL
Explanation:
To calculate the volume of a solution before dilution, we make use of the dilution formula;
C1 V1 = C2 V2
C1 = the concentration of the stock solution = 15 M
V 1 = the volume of stock solution = ?
C2 = concentartion of final solution = 2.35 M
V2 = volume of final solution = 250 mL = 250/ 1000 = 0.25 L
Rearranging the formula, we obtain;
V1 = C2V2 / C1
V 1 = 2.35 * 0.25 / 15
V1 = 0.5875 / 15
V1 = 0.0392 L
the initial volume of the stock solution is 0.0392 L or 39.2 mL
Answer:
Thermal energy typically flows from a warmer material to a cooler material.
Explanation:
