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3 years ago

Calculate the mass of aluminum that would have the same number of atoms as 6.35 g of cadmium

Chemistry

1 answer:

Sergeu [11.5K]3 years ago

6 0

Answer:

1.62 g of Al contain the same number of atoms as 6.35 g of cadmium have.

Explanation:

Given data:

mass of cadmium = 6.35 g

Number of atoms of aluminum as 6.35 g cadmium contain = ?

Solution:

Number of moles of cadmium = 6.35 g/ 112.4 g/mol

Number of moles of cadmium = 0.06 mol

Number of atoms of cadmium:

1 mole = 6.022×10²³ atoms of cadmium

0.06 mol × 6.022×10²³ atoms of cadmium/ 1mol

0.36×10²³ atoms of cadmium

Number of atoms of Al:

Number of atoms of Al = 0.36×10²³ atoms

1 mole = 6.022×10²³ atoms

0.36×10²³ atoms × 1 mol /6.022×10²³ atoms

0.06 moles

Mass of aluminum:

Number of moles = mass/molar mass

0.06 mol = m/ 27 g/mol

m = 0.06 mol ×27 g/mol

m = 1.62 g

Thus, 1.62 g of Al contain the same number of atoms as 6.35 g of cadmium have.

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Now,

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3 years ago

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(III) CO(NH₂)₂ + ³/₂O₂ → CO₂ + 2H₂O + N₂; ΔH = -632 kJ

From these, we must devise the target equation:

(IV) 2NH₃ + CO₂ → CO(NH₂)₂ + H₂O; ΔH = ?

_________________________________

The target equation has 2NH₃ on the left, so you reverse equation (I).

When you reverse an equation, you reverse the sign of its ΔH.

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Equation (V) has 1N₂ on the right, and that is not in the target equation.

You need an equation with 1N₂ on the left.

Reverse Equation (III).

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Equation (VI) has ³/₂O₂ on the right, and that is not in the target equation.

You need ³/₂O₂ on the left.

Multiply Equation (II) by three.

When you multiply an equation by three, you multiply its ΔH by three.

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Now, you add equations (V), (VI), and (VII), cancelling species that appear on opposite sides of the reaction arrows.

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_______________________________________

We get the target equation (IV):

(V) 2NH₃ → N₂ + 3H₂; ΔH = + 92 kJ

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2 years ago

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Answer:

The increasing order of masses of molecule ions:

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Atomic mass of 37-Cl = 37 g/mol

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Mass of Chlorocyclohexane in which 37-Cl is present as a chlorine atom: $C_6H_{11}Cl$

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The increasing order of masses of molecule ions:

118 g/mol(75.8%) < 120 g/mol(24.2%)

5 0

3 years ago

Calculate the mass of aluminum that would have the same number of atoms as 6.35 g of cadmium ​

Calculate the mass of aluminum that would have the same number of atoms as 6.35 g of cadmium