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Lyrx [107]
2 years ago
14

Please help me answering this question

Computers and Technology
1 answer:
Vanyuwa [196]2 years ago
8 0

Answer:

none of them

Explanation:

the resistor is connected to the + pole of the battery, no circuit shows that.

a 1kΩ resistor would be brown-black-red, not brown black black.

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Problem 2 Write a method that (a) returns an int[] , (b) takes in two sorted arrays (in descending order) and (c) returns an int
Galina-37 [17]

Answer:

Following are the Program in the Java Programming Language.

//define class

public class Main

{

//define function to merge and sort array

public static int[] sort_Array(int[] a, int[] b)

{

//set integer variable and initialize values

int x = 0, y = 0, k = 0, num = 0;

int n = a.length;

int n1 = b.length;

//set integer type array

int[] ar = new int[n+n1];

//set while loop

while (x<n && y <n1)

{

num++;

num++;

//set if conditional statement

if (a[x] > b[y])

ar[k++] = a[x++];

else

ar[k++] = b[y++];

num++;

}

//set the while loop

while (x < n)

{

num++;

ar[k++] = a[x++];

}

//set the while loop

while (y < n1)

{

num++;

ar[k++] = b[y++];

}

//print the total compares done

System.out.println("Number of compares done: " + n);

//return array

return ar;

}

//define main method

public static void main(String[] args)

{

//declaration and the initialization of array

int[] a = new int[]{18,16, 15, 6, 2};

int[] b = new int[]{13, 12, 11, 7, 1};

int[] ar;

//call function

ar = sort_Array(a, b);

//print message

System.out.println("\nThe resultant array is: \n");

//set for loop to print array

for(int x=0; x<ar.length; x++)

{

System.out.print(ar[x] + " ");

}

}

}

<u>Output</u>:

Number of compares done: 5

The resultant array is:

18 16 15 13 12 11 7 6 2 1

Explanation:

Here, we define a class "Main" inside the class, define a function "sort_Array()"and pass two integer type array argument "a" and "b".

  • Set four integer type variables "x", "y", "k", and "num" and initialize them to 0.
  • Set two integer type array "n", "n1" and initialize them the length of the array then, set integer type array variable "ar".
  • Set the while loop then, set if conditional statement then, agin set while loop to sort array in descending order.
  • Then, print the number of compares and return the value of the variable "ar".

Finally, define the main method inside it, we set two integer type array variable and initialize elements in them then, set the for loop to print the sorted elements of the array.

4 0
3 years ago
What is one purpose of an algorithm
adelina 88 [10]

Answer:

Algorithms is formula for solving a problem. It is helpful because it specifically give instructions detail to computer to what a computer should perform a specific task.

For e.g. calculating report cards.

4 0
3 years ago
Write a program that simulates a lottery. The program should havean array of five integers named lottery, and shouldgenerate a r
Fiesta28 [93]

Answer:

Here is the C++ program that simulates lottery:

#include<iostream>  //to use input output functions

using namespace std;  //to access objects cin cout

int main(){  //start of main function

int size= 5; // size of arrays

int range = 10;  //range of random numbers from 0 to 9

int user[size];  // user array

int lottery[size];  // lottery array

for(int i=0;i<size;i++)  //iterates through the array

lottery[i]=rand()%range;  // generates random number in specified range

cout<<"Enter "<<size<<" digits: ";  //prompts user to enter 5 digits

for(int i=0;i<size;i++)  //loops through the user array

cin>>user[i];  //reads input digits from user

int match=0;  //stores number of matching digits

for(int i=0;i<size;i++)  //iterates through array to compare user and lottery arrays

if(user[i]==lottery[i])  //if digit at i-th index of user array matches to that of lottery array

match++;  //increments count of matching digits by 1

cout<<"Lottery array: ";  // display digits of lottery array

for(int i=0;i<size;i++)  //iterates through elements of lottery array

cout<<lottery[i]<<" ";  //prints elements of lottery array with a space between them

cout<<endl;  //prints a new line

cout<<"  User  array: ";  // prints digits of user array

for(int i=0;i<size;i++) //iterates through elements of user array

cout<<user[i]<<" ";  //prints elements of user array

cout<<endl;  // prints a new line

if(match==size){  //if all the digits match

cout<<"Congratulations. You are a grand prize winner! "; }//displays this message proclaiming the user as a grand prize winner

else{  // if all digits of user array do not match with lottery array digits

cout<<"Number of digits matched: "<<match<<endl; //displays the number of matched digits

cout<<"Sorry! Better luck next time!" ;    //displays this message when all digits don't match

}

}    

Explanation:

If you want to keep the size and range fixed then you can use #define before the main() function to give a constant value to size and range as:

#define size 5

#define range 10

The program uses rand() function in order to generate random numbers for lottery array in the range of 0 through 9.

Then the program declares a user array with size = 5 and prompts user to enter 5 digits to stores in user array.

Next the program matches each digit of user array to the corresponding digit of lottery array and if the two digits match then the program increments the match variable by 1 to count the matched digits. For example, lets say lottery has the following elements:

lottery: 7,4,9,1,3

Lets say user array has following elements input by user at console

user: 4,2,9,7,3

Now at first iteration the digit 7 at 0-th index of lottery array is matched to the digit 4 at 0-th index of user array. This index is specified using variable i. These means the first element of lottery array is matched with first element of user array. As these digits are not equal so they don't match and the variable i is incremented to point to the position of next digit.

Now at second iteration the digit 4 in lottery array is matched to the digit 2 of user array. As these digits are not equal so they don't match and the variable i is incremented.

at third iteration the digit 9 in lottery array is matched to the digit 9 of user array. As these digits equal so they match and the variable match is incremented to 1 in order to count the number of matches. So value of match = 1

Now at fourth iteration the digit 1 in lottery array is matched to the digit 7 of user array. As these digits are not equal so they don't match and the variable i is incremented. The value of match also remains the same i.e. 1

at fifth iteration the digit 3 in lottery array is matched to the digit 3 of user array. As these digits equal so they match and the variable match is incremented to 1 in order to count the number of matches. So value of match = 2

Next the loop ends because the value of exceeds 5 which is the size of the array.

Next if(match==size) statement has an if condition which checks if all digits match. This is checked by comparing the count of match variable to the size of the array. The value of match is 2 and value of size is 5 so this means that all the digits do not match. Hence this condition evaluates to false. So the statement in if part will not execute and program moves to the statement: cout<<"Number of digits matched: "<<match<<endl; which displays the value of match variable i.e. 2 as:

Number of digits matched: 2

followed by statement cout<<"Sorry! Better luck next time!" ;  which displays the message:

Sorry! Better luck next time!

5 0
3 years ago
Look at the following code.int x = 7;int *iptr = &amp;x;What will be displayed if you send the expression *iptr to cout ? What h
masha68 [24]

Answer:

The answer to the given question can be given as:

The value of *iptr is 7. and the value of iptr is dynamic.

Explanation:

In the c++ code, it is defined that x is an integer variable that assigns a value which is 7. Then we define a pointer variable that is *iptr. This variable holds an address of the x variable. When we print the value of the iptr variable. if we use the expression *iptr to print value of the pointer variable by cout that is used in c++ for pint values. so the value of the iptr is 7. If we use the expression iptr sent to cout so we show the address of the variable x. In the pointer, it manages the addresses of dynamically allocated so the address of the variable is changed on execution time.

4 0
3 years ago
To enable grammar correction in powerpoint, you must first enable office ____ services.
sesenic [268]

Answer:

Grammar

Explanation:

8 0
2 years ago
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