HELP ME PLEASE GUYS THANKS!

Whats the equation of the line that passes threw -4,4 and is parrell to the line y=1/2-4

vovangra [49]

Answer:

$y=\frac{1}{2}x+6$

Step-by-step explanation:

Given:

The equation of the known line is:

$y=\frac{1}{2}x-4$

A point on the unknown line is (-4, 4)

Now, since the two lines are parallel, their slopes must be equal.

Now, slope of the known line is the coefficient of 'x' which is $\frac{1}{2}$ .

Therefore, the slope of the unknown line is also $m=\frac{1}{2}$

Now, for a line with slope 'm' and a point on it $(x_1,y_1)$ is given as:

$y-y_1=m(x-x_1)$

Here, $m=\frac{1}{2}, x_1=-4,y_1=4$ . Therefore,

$y-4=\frac{1}{2}(x-(-4))\\\\y-4=\frac{1}{2}(x+4)\\\\y-4=\frac{1}{2}x+2\\\\y=\frac{1}{2}x+2+4\\\\y=\frac{1}{2}x+6$

Hence, the equation of the unknown line is $y=\frac{1}{2}x+6$ .

5 0

4 years ago

A number is squared. The result is squared, then that result is squared. The final number is 6561

larisa [96]

The question is saying a number is square, then squared again, and finally square again, making that number squared itself up to 3 times. So we take 6561 and we square root it 3 times. Square root of 6561 is 81, square of 81 is 9, and finally square root if 9 is 3. The final answer is 3.

8 0

3 years ago

What is the difference between bernoulii equation and riccati equation

melisa1 [442]

The Bernoulli equation is almost identical to the standard linear ODE.

$y'=P(x)y+Q(x)y^n$

Compare to the basic linear ODE,

$y'=P(x)y+Q(x)$

Meanwhile, the Riccati equation takes the form

$y'=P(x)+Q(x)y+R(x)y^2$

which in special cases is of Bernoulli type if $P(x)=0$ , and linear if $R(x)=0$ . But in general each type takes a different method to solve. From now on, I'll abbreviate the coefficient functions as $P,Q,R$ for brevity.

For Bernoulli equations, the standard approach is to write

$y'=Py+Qy^n$
$y^{-n}y'=Py^{1-n}+Q$

and substitute $v=y^{1-n}$ . This makes $v'=(1-n)y^{-n}y'$ , so the ODE is rewritten as

$\dfrac1{1-n}v'=Pv+Q$

and the equation is now linear in $v$ .

The Riccati equation, on the other hand, requires a different substitution. Set $v=Ry$ , so that $v'=R'y+Ry'=R'\dfrac vR+Ry'$ . Then you have

$y'=P+Qy+Ry^2$
$\dfrac{v'-R'\dfrac vR}R=P+Q\dfrac vR+R\dfrac{v^2}{R^2}$
$v'=PR+\left(Q+\dfrac{R'}R\right)v+v^2$

Next, setting $v=\dfrac{u'}u$ , so that $v'=\dfrac{uu''-(u')^2}{u^2}$ , allows you to write this as a linear second-order equation. You have

$\dfrac{uu''-(u')^2}{u^2}=PR+\left(Q+\dfrac{R'}R\right)\dfrac{u'}u+\dfrac{(u')^2}{u^2}$
$u''-\left(Q+\dfrac{R'}R\right)u'+PRu=0$
$u''+Su'+Tu=0$

where $S=-\left(Q+\dfrac{R'}R\right)$ and $T=PR$ .

3 0

3 years ago

The ticket sales for a concert started at 4:00 P.M. The table shows the linear relationship

Vadim26 [7]

Answer: J. for people in Ed or y = -3,000x + 15,000

Step-by-step explanation:

4 0

3 years ago

3. When 25 is added to 7 times a number, the result is 81. Find the number.

Dominik [7]

Answer:

3. 2.5

4. $5 per candy bar

5. You mowed 6 lawns

6. 15.66 is the number

7. 13 weeks

8. 135 students came

9. 12

Step-by-step explanation:

3. 25+7= 32.

81/32= 2.5

4. 23-3= 20

20/4= 5

5. 155-35=120

120/20=6

6. 10-4 = 6

94/6=15.66

(not 100% sure about this one)

7. 200-161=39

39/3=13

8. 975-300=675

675/5=135

9. 36-12=24

36/3= 12

(not 100% sure about this one)

Bonus: Sorry I don't know

I hope I can help! Also next time do each question one by one so other people can answer and not answer all of them if they don't know one.

4 0

3 years ago