Answer:
90% CI expects to capture u 90% of time
(a) This means 0.9 * 1000 = 900 intervals will capture u
(b) Here we treat CI as binomial random variable, having probability 0.9 for success
n = 1000
p = 0.9
For this case, applying normal approximation to binomial, we get:
mean = n*p= 900
variance = n*p*(1-p) = 90
std dev = 9.4868
We want to Find : P(890 <= X <= 910) = P( 889.5 < X < 910.5) (integer continuity correction)
We convert to standard normal form, Z ~ N(0,1) by z1 = (x1 - u )/s
so z1 = (889.5 - 900 )/9.4868 = -1.11
so z2 = (910.5 - 900 )/9.4868 = 1.11
P( 889.5 < X < 910.5) = P(z1 < Z < z2) = P( Z < 1.11) - P(Z < -1.11)
= 0.8665 - 0.1335
= 0.733
Answer:
1) 33.33%
2) 16.66%
Step-by-step explanation:
1) Since multiples of 3 in 1,2,3,4,5,6 include and limited to 3 and 6. This means that 2 / 6 or 1 / 3. This fraction is equal to 33.33%.
2) Since multiples of 4 in 1,2,3,4,5,6 include and limited to only 4. This means that 1/6 and this fraction is equal to 16.66%.
Can you please post a photo or something so we can help you?!
Answer:
the purple one
Step-by-step explanation:
