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alexandr402 [8]
4 years ago
13

Two atoms interact with each other as shown by the equation. Complete the equation by filling in the missing parts,

Chemistry
2 answers:
strojnjashka [21]4 years ago
8 0
2...............................
pashok25 [27]4 years ago
7 0

The question is incomplete, here is the complete question:

Two atoms interact with each other as shown by the equation. Complete the equation by filling in the missing parts.

_1^2\textrm{H}+_1^2\textrm{H}\rightarrow _Z^A\textrm{X}+_0^1\textrm{n}

<u>Answer:</u> The isotopic symbol of the missing part is _{2}^{3}\textrm{He}

<u>Explanation:</u>

In a nuclear reaction, the total mass and total atomic number remains the same.

For the given fusion reaction:

_1^2\textrm{H}+_1^2\textrm{H}\rightarrow _Z^A\textrm{X}+_0^1\textrm{n}

  • <u>To calculate A:</u>

Total mass on reactant side = total mass on product side

2 + 2 = A + 1

A = 3

  • <u>To calculate Z:</u>

Total atomic number on reactant side = total atomic number on product side

1 + 1 = Z

Z = 2

Hence, the isotopic symbol of the missing part is _{2}^{3}\textrm{He}

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Evaporation of Cane Sugar Solutions. An evaporator is used to concentrate cane sugar solutions. A feed of 10 000 kg/d of a solut
Vera_Pavlovna [14]

Answer:

Weight of solution produced = 5135 kg

Amount of water removed = 4865 kg

Explanation:

For the balance of mass, the incoming mass of sugar must be equal to the outgoing mass. So, the incoming mass (mi) is 38% of 10000 kg

mi = 0.38x10000 = 3800 kg

The outgoing mass (mo) must be 3800 kg, and it is 74% of the total mass (mt)

mo = 0.74xmt

0.74xmt = 3800

mt = 3800/0.74

mt = 5135 kg

This is the mass of solution produced.

The amount of water removed (wr) is the amount of water incoming (wi) less the amount of water outgoing (wo). Both will be the total mass less the mass of sugar :

wi = 10000 - 3800 = 6200 kg

wo = 5135 - 3800 = 1335 kg

wr = wi - wo

wr = 6200 - 1335

wr = 4865 kg

8 0
4 years ago
At high temperatures, carbon reacts with O2 to produce CO as follows: C(s) O2(g) 2CO(g). When 0.350 mol of O2 and excess carbon
777dan777 [17]

Answer:

Value of K_{c} is 0.090.

Explanation:

Initial molarity of O_{2} = \frac{0.350}{5.00}M = 0.0700 M

Construct an ICE table corresponding to the combustion reaction of carbon to determine K_{c}

                       C(s)+O_{2}(g)\rightarrow 2CO(g)

              I (M):    -      0.0700        0

             C (M):  -          -x             +2x

             E (M):   -    0.0700-x       2x

So, K_{c}=\frac{[CO]^{2}}{[O_{2}]}  , where [CO] and [O_{2}] represents equilibrium concentration of CO and O_{2} respectively.

Here, [CO]=2x=0.060

       ⇒x = 0.030

So, [O_{2}] = 0.0700-x = (0.0700-0.030) = 0.040

Hence,  K_{c}=\frac{(0.060)^{2}}{0.040}=0.090

4 0
4 years ago
A student checks the air in her bicycle tires early in the morning when it is cool outside. If she measures it again later in th
Dmitry_Shevchenko [17]

Answer:

She will observe that the pressure on the tire is higher.

Explanation:

By the ideal gas law, the pressure and the temperature are directly proportional, so, if the temperature increases the pressure increases too:

PV = nRT (P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature).

The temperature is a measure of the average kinetic energy of the gas molecules, so when the temperature increases, the energy also increases, and the gas molecules will move more quickly, so they will collide more often between themselves and in the wall. Those collisions will be with more force because the velocity is higher.

So, the pressure will be higher, because it is the result of collisions of the gas molecules with the walls of the tire.

6 0
3 years ago
Next to each formula, write the number of atoms of each element found in one unit of the compound
satela [25.4K]
To answer this question I would have to know the elements in the compound
7 0
4 years ago
Energy from the sun travels to the earth through
julia-pushkina [17]

Answer:

D. Infrared Radiation

I hope this helps.

8 0
3 years ago
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