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3 years ago

11

How much of the matter in the universe is comprised of atoms?

2 answers:

andreyandreev [35.5K]3 years ago

7 0

Answer:

4.6%.

Explanation:

Actually, the belief before few decades ago is that the whole of the universe comprises of atoms, you, me, stars and so on comprises of atoms that is protons, neutrons and electrons but now according to some researches made, the whole of the universe does not contain atoms naturally as their are some unseen things in the universe. According to the researches by astrophysicists the universe contains about 4.6 percent atoms and the others are dark energy which has the largest portion of the universe of about 71.4 percent and cold dark matter which contains about 24 Percent of the universe.

Deffense [45]3 years ago

4 0

Explanation:

Atoms are the components of ordinary matter, also called baryonic matter, which only represents 4% of the universe, while the remaining 96% would be formed by what is known as dark matter and dark energy which constitute two of the unsolved problems in physics.

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A radar for tracking aircraft broadcasts a 12 GHz microwave beam from a 2.0-m-diameter circular radar antenna. From a wave persp

NISA [10]

A) 750 m

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$f=12GHz=12\cdot 10^9 Hz$ is the frequency

$c=3.0\cdot 10^8 m/s$ is the speed of light

So the wavelength of the beam is

$\lambda=\frac{c}{f}=\frac{3\cdot 10^8 m/s}{12\cdot 10^9 Hz}=0.025 m$

Now we can use the formula of the single-slit diffraction to find the radius of aperture of the beam:

$y=\frac{m\lambda D}{a}$

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m = 1 since we are interested only in the central fringe

D = 30 km = 30,000 m

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$y=\frac{(1)(0.025 m)(30000 m)}{2.0 m}=375 m$

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B) 0.23 W/m^2

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$r=\frac{750 m}{2}=375 m$

So the area is

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And since the power is

$P=100 kW = 1\cdot 10^5 W$

The average intensity is

$I=\frac{P}{A}=\frac{1\cdot 10^5 W}{4.42\cdot 10^5 m^2}=0.23 W/m^2$

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3 years ago