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Otrada [13]
2 years ago
6

I need help pls :((((((

Mathematics
1 answer:
Elodia [21]2 years ago
6 0

Answer:

Step-by-step explanation:

for the first one scale by 2 and the second one scale by 1/2 (the easiest ones)

sides would be 20,12,16 for the first one and 5,3,4 for the second one

1 keeps the tri the same size because your muti0lyong by one

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Does this set of ordered pairs represent a function? (-1,5)(0,-3)(2,7)(4,0)(7,5)
ruslelena [56]

Answer:

No

Step-by-step explanation:

You cant have 2 y values

6 0
3 years ago
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if there are 12 dogs that sell for $104 and 8 cats that sell for $25. At the end of the day there are 4 dogs left and 5 cats lef
Vinil7 [7]

Initially there were 12 dogs

dogs left at the end of day =4

number of dogs sold=12-4=8

price of one dog=$104

price of 8 dogs = 104*8= $832

initially there were 8 cats

cats left at the end of day =5

number of cats sold =8-5=3

price of one cat= $25

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3 years ago
What is the discrimination of the quadratic equation 6x^2-9x-8=0
aleksklad [387]

Answer:

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6 0
3 years ago
Find the number in which 4 has highest value.
Andru [333]

Step-by-step explanation:

the number in which 4 has the highest value is

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7 0
2 years ago
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Find the least common multiple for 6(x+1)^3(x-4)^2 and 10(x+1)^8(x-4)^5
dolphi86 [110]

Answer:

30(x+1)^8 (x-4)^5

Step-by-step explanation

<h3>6(x+1)^{3}(x-4))^{2}=2X3 X (x+1)^3(x-4)^2\\10(x+1)^8(x-4)^5)= 2X5X(x+1)^8 (x-4)^5\\</h3>

In order to find the Least common multiple we write each of the factor only once from each of the expression and for the common expression we take their LCM as maximum of the exponent in  all expressions

as here in the question exponent of (x+1) are 3 and 8 so we take exponent 8

likewise for (x-4) we shall take maximum of 2 and 5 which is 5

so our expression for Least common multiple will be

2X3X5 X (x+1)^8 (x-4)^5

30(x+1)^8 (x-4)^5

7 0
3 years ago
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