There are ________ mol of bromide ions in 0.700 L of a 0.400 M solution of AlBr
1 answer:
Answer:
The number of moles of AlBr3 = Molarity × Volume
= 0.400 × 0.700
= 0.28 moles
1 mole of AlBr3 gives 3 moles of Br- ions
That is
AlBr3 = Al3+ + 3Br-
Therefore, 0.045 moles of AlBr3 will yield 3 × 0.28 = 0.84 moles
Thus; they are 0.84 moles of bromide ions
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