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sineoko [7]
3 years ago
11

Please help me do three

Chemistry
1 answer:
Orlov [11]3 years ago
6 0

Answer:

3a) (NH₄)₂ CO₂

b) FeF₂

c) CaN₂

d) Al₂O₃

e) NiCl₂

f) Mg₃P₂

g) KHCO₃

h) PbOH₂

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3 years ago
The boiling point elevation of an aqueous sucrose solution is found to be 0.39°C.
SVEN [57.7K]

Answer:

130.4 grams of sucrose, would be needed to dissolve in 500 g of water.

Explanation:

Colligative property of boiling point elevation:

ΔT = Kb . m . i

In this case, i = 1 (sucrose is non electrolytic)

ΔT = Kb . m

0.39°C = 0.512°C/m . m

0.39°C /0.512 m/°C = m

0.762 m (molality means that this moles, are in 1kg of solvent)

If in 1kg of solvent, we have 0.712 moles of sucrose, in 500 g, which is the half, we should have, the hallf of moles, 0.381 moles

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6 0
4 years ago
Hi please help me i only have 2 days to do all of this
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3 years ago
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How do you convert from Fahrenheit to Celsius temperatures
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The number 0.0020 expressed in scientific notation is?
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