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kompoz [17]
2 years ago
5

A common drinking glass is 7 cm in diameter and fi lled to a depth of 12 cm with water. Calculate the pressure difference betwee

n the top and bottom of the glass sides.
Physics
1 answer:
Dahasolnce [82]2 years ago
8 0

Answer:

Answer is 5

Explanation:

the bottom of the glass sides pressure is high than the top

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Derive the expression for the range of the ball as a function of its height. To do this you should use the following steps. In t
AVprozaik [17]

Explanation:

Thanks for this....

its very helpful...

4 0
3 years ago
a hockey puck with a mass of 0.11 kg is at rest on the horizontal frictionless surface of the rink. a player applies a horizonta
stira [4]

The solution to this ques is available in the image.

Given,

Force= 1N

Mass= 0.11kg

Time= 5sec

Force= mass X accelaration

Accelaration= velocity/ time

Speed=distance/ time

Hence, the speed is 45 m/s and the distance is 225 m.

To know more about speed and distance problems the link is given below:

brainly.com/question/19610984?

#SPJ4

8 0
2 years ago
A bowling ball of mass 5 kg rolls down a slick ramp 20 meters long at a 30 degree angle to the horizontal. What is the work done
Elena-2011 [213]

Answer:

The work done by gravity during the roll is 490.6 J

Explanation:

The work (W) is:

W = F*d

<em>Where</em>:

F: is the force

d: is the displacement = 20 m

The force is equal to the weight (W) in the x component:

F = W_{x} = mgsin(\theta)

<em>Where:</em>

m: is the mass of the bowling ball = 5 kg

g: is the gravity = 9.81 m/s²    

θ: is the degree angle to the horizontal = 30°        

F = mgsin(\theta) = 5 kg*9.81 m/s^{2}*sin(30) = 24.53 N    

Now, we can find the work:

W = F*d = 24.53 N*20 m = 490.6 J      

Therefore, the work done by gravity during the roll is 490.6 J.

I hope it helps you!

6 0
3 years ago
14. If the spring constant of a simple harmonic oscillator is doubled, by what factor will the mass of the system need to change
klio [65]

Lets se

And

\\ \rm\Rrightarrow T=2\pi\sqrt{\dfrac{m}{k}}

\\ \rm\Rrightarrow \sqrt{k}T=2\pi\sqrt{m}

So

\\ \rm\Rrightarrow k\propto m

If spring constant is doubled mass must be doubled

8 0
2 years ago
Can anyone plz help me ​
Alekssandra [29.7K]

Answer:

1.) volume = 8 cm^3

2.) density = 2.6 g/cm^3

Explanation:

1.) volume =

side {}^{3}

=》

{2}^{3}

=》

8 \: cm {}^{3}

2.) density =

\frac{mass}{volume}

=》

\frac{20.8}{8}

=》

2.6 \: g \: cm {}^{ - 3}

density = 2.6

3 0
3 years ago
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