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professor190 [17]
3 years ago
11

Which instrument should, ideally, have zero resistance?

Physics
2 answers:
Temka [501]3 years ago
6 0
The answer is C voltmeter
MrMuchimi3 years ago
5 0
I think the answer is D) ammeter, because the resistance of the ammeter has to zero, to ensure there is no error readings during measurements.
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A hockey puck is sliding across a frozen pond with an initial speed of 9.5 m/s. It comes to rest after sliding a distance of 37.
Bond [772]

Answer:

<h3>The coefficient of kinetic friction between the puck and the ice is \mu _{k} = 0.12</h3>

Explanation:

Given :

Initial speed  v_{o} = 9.5 \frac{m}{s}

Displacement x = 37.4 m

From the kinematics equation,

  v^{2} - v^{2} _{o}  = 2ax

Where v^{2}   = final velocity, in our example it is zero (v =0), a = acceleration.

   a =- \frac{90.25}{ 2 \times 37.4}

   a =- 1.21 \frac{m}{s^{2} }

From the formula of friction,

  F =- \mu _{k } N

Minus sign represent friction is oppose the motion

Where N = mg ( normal reaction force )

 ma = -\mu _{k}  m g                                                  ( ∵ g = 9.8 \frac{m}{s^{2} } )

So coefficient of friction,

 \mu_{k} = \frac{1.21}{9.8}

 \mu_{k} = 0.12

Therefore, the coefficient of kinetic friction between the puck and the ice is  \mu _{k} = 0.12 .

4 0
3 years ago
What would be the magnitude of the electric field 0.75 m from a 0.63 C master charge and what would be the force on a 0.50 C tes
bagirrra123 [75]

The magnitude of the electric field on the master charge is 1.008 x 10¹⁰ N/C, and the force on the test charge is 5.04 x 10⁹ N.

<h3>Electric field on the master charge</h3>

E = kq/r²

where;

  • q is magnitude of master charge
  • r is distance of separation
  • k is Coulomb's constant

E = (9 x 10⁹ x 0.63)/(0.75²)

E = 1.008 x 10¹⁰ N/C

<h3>Force on the test charge</h3>

F = Eq

where;

  • E is electric field
  • q is the test charge

F = (1.008 x 10¹⁰) x (0.5)

F = 5.04 x 10⁹ N

Thus, the magnitude of the electric field on the master charge is 1.008 x 10¹⁰ N/C, and the force on the test charge is 5.04 x 10⁹ N.

Learn more about electric field here: brainly.com/question/14372859

#SPJ1

8 0
2 years ago
Which force is represented by the arrow at A?
Tanzania [10]

Answer:Gravity is a force of attraction that exists between any two masses, any two bodies, any two particles. Gravity is not just the attraction between objects and the Earth. It is an attraction that exists between all objects, everywhere in the universe.Friction is the resistance to motion of one object moving relative to another. It is not a fundamental force, like gravity or electromagnetism. Instead, scientists believe it is the result of the electromagnetic attraction between charged particles in two touching surfaces.

The normal force is the force that surfaces exert to prevent solid objects from passing through each other. Normal force is a contact force. If two surfaces are not in contact, they can't exert a normal force on each other.The tension force is defined as the force that is transmitted through a rope, string or wire when pulled by forces acting from opposite sides. The tension force is directed over the length of the wire and pulls energy equally on the bodies at the ends.

Explanation:

3 0
3 years ago
Which are the main regions of the periodic table? A. metals, nonmetals, gases B. solids, liquids, gases C. metals, semimetals, n
nlexa [21]

Answer:

the answer is C.

Explanation:

8 0
4 years ago
At the instant the traffic light turns green, a car that has been waiting at an intersection starts ahead with a constant accele
EleoNora [17]

Answer:

306.8264448 m

47.0016 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

Distance traveled by car

s_c=ut+\dfrac{1}{2}at^2\\\Rightarrow s_c=\dfrac{1}{2}at^2

Distance traveled by truck

s_t=ut

In order to overtake both distances should be equal

\dfrac{1}{2}at^2=ut\\\Rightarrow \dfrac{1}{2}at=u\\\Rightarrow t=\dfrac{2u}{a}\\\Rightarrow t=\dfrac{2\times 23.5}{3.6}\\\Rightarrow t=13.056\ s

s_c=\dfrac{1}{2}at^2\\\Rightarrow s_c=\dfrac{1}{2}3.6\times 13.056^2\\\Rightarrow s_c=306.8264448\ m

The distance the car has to travel is 306.8264448 m

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 3.6\times 306.8264448+0^2}\\\Rightarrow v=47.0016\ m/s

The speed of the car when it overtakes the truck is 47.0016 m/s

8 0
3 years ago
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