Answer:
the rocks are away from cracks in the crust
Explanation:
The new crust is pushed away from the Ocean Ridge in both directions as newer crust is formed. This is called sea floor spreading. The crust that makes up the sea floor starts to have time to accumulate a layer of sediments as it gets older and moves away from the Ocean Ridge.
Answer:
3.78 m on the left side of the seesaw
Explanation:
The net torque in this situation is zero, so the torque from each side of the pivot point must balance each other out:
(50.0 kg x 10.0 m/s^2)(3.4m) = (450 N) r
Solve for r, and you get 3.78 on the left side.
Hope this helps!
The time interval needed for the disk to rev from leave to 25.0 m/s
= 0.57 s
<h3>What is the time interval?</h3>
- A larger period of time can be split up into multiple shorter, equal-length segments.
- These are referred to as time periods. Consider the scenario where you wished to gauge a car's speed over an hour-long trip. You could break up an hour into ten-minute segments.
- In Hz, frequency is defined as the number of cycles per second. Simply divide 1 by the frequency to determine the time interval for a known frequency (e.g., a frequency of 100 Hz has a time interval of 1/(100 Hz) = 0.01 seconds; 500 Hz has a time interval of 1/(500Hz) = 0.002 seconds, etc.).
Given:
vo = 0
v = 25.4 m/s
r = 0.95 m
n = 1.21 rev
A.
r*ω = v
ω = v/r
= 25.4/.95
= 26.74 rad/s
B.
θ = 2πn
= 2π × (1.21)
= 7.6 m
Using equation of motion,
ωf^2 = ωi^2 + 2αθ
(26.74)^2 = 2 × α × (7.6)
α = 715.03/15.2
= 47.04 rad/s^2
C.
Using equation of motion,
θ = ωi*t + 1/2*α*t^2
θ = 0 + 1/2*α*t^2
7.6 = 47.04/2 × t^2
= sqrt(0.323)
= 0.57 s
Therefore the correct answer is 0.57 s
To learn more about time interval, refer to:
brainly.com/question/479532
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