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2 years ago

A particle could have a charge of

1 answer:

7 0

The correct answer is
<span> (3) 3.2 × 10^−19 C

In fact, electric charge is quantized: the elementary charge is the charge of the electron, </span> $e=1.6 \cdot 10^{-19} C$ , and every particle can only have an electric charge which is an integer multiple of this value. Of the options listed above, only option (3) is an integer multiple of the elementary charge: in fact, it corresponds to 2 times the electron charge:
$2e=2 \cdot 1.6 \cdot 10^{-19} C=3.2 \cdot 10^{-19} C$

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Can somebody help me on finding the constants if this experiment?

ki77a [65]

The constants could be the day because the experiment is all on the same day or the person throwing the pumpkin because it will always be the same perosn

8 0

3 years ago

We define the specific heat of a material as the energy that must be transferred to 1.0 kg of that material in order to cause it

Nezavi [6.7K]

Answer:

No change in the specific heat.

Explanation:

Specific heat is an intrinsic property that it has not depend upon on the amount of substance or energy added, it depends upon the material.

So, when twice the amount of energy is transferred, specific heat of the material does not change rather the energy that is twice in the amount to 1 kg of that material cause it to warm 2.0° C.

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2 years ago

A 5.30 m long pole is balanced vertically on its tip. What will be the speed (in meters/second) of the tip of the pole just befo

suter [353]

Answer:

v = 17.66 m/s

Explanation:

As we know that the lower end of the pole is fixed in the ground and it start rotating about that end

so here we can say that the gravitational potential energy of the pole will convert into rotational kinetic energy of the pole about its one end

so we have

$mgL = \frac{1}{2}(\frac{mL^2}{3})\omega^2$

so we have

$\omega = \sqrt{\frac{6g}{L}}$

now we have

$\omega = \sqrt{\frac{6(9.81)}{5.30}}$

$\omega = 3.33 rad/s$

now the speed of the other tip of the pole is given as

$v = \omega L$

$v = (3.33)(5.30) = 17.66 m/s$

8 0

3 years ago

Which of the following phrases describes a motor?

Delicious77 [7]

Your answer is d I believe

7 0

2 years ago

Given vectors D (3.00 m, 315 degrees wrt x-axis) and E (4.50 m, 53.0 degrees wrt x-axis), find the resultant R= D + E. (a) Write

fomenos

Answer:

(a) $\vec{R}= 4.83\ m\ \hat{i}+1.47\ m\ \hat{j}$

(b) (5.05 m, 16.93 degrees wrt x-axis)

Explanation:

Given:

$\vec{D}$ = (3.00 m, 315 degrees wrt x-axis)
$\vec{E}$ = (4.50 m, 53.0 degrees wrt x-axis)

Let us first fond out vector D and E in their rectangular form.

$\vec{D} = (3\cos 315^\circ\ \hat{i}+3\sin 315^\circ\ \hat{j})\ m\\\Rightarrow \vec{D} = (2.12\ \hat{i}-2.12\ \hat{j})\ m\\$

Similarly,

$\vec{E} = (4.5\cos 53^\circ\ \hat{i}+4.5\sin 53^\circ\ \hat{j})\ m\\\Rightarrow \vec{D} = (2.71\ \hat{i}+3.59\ \hat{j})\ m\\\because \vec{R}=\vec{D}+\vec{E}\\\therefore \vec{R} = (2.12\ \hat{i}-2.12\ \hat{j})\ m+(2.71\ \hat{i}+3.59\ \hat{j})\ m\\\Rightarrow \vec{R} = (4.83\ \hat{i}+1.47\ \hat{j})\ m$

Part (a):

We can write the resultant vector R as below:

$\vec{R} = (4.83\ \hat{i}+1.47\ \hat{j})\ m$

Part (b):

$Magnitude\ of\ resultant = \sqrt{4.83^2+1.47^2}\ m = 5.05\ m\\\textrm{Direction in angle with the x-axis} = \theta = \tan^{-1}(\dfrac{1.47}{4.83})= 16.93^\circ$

Since both the components of the resultant lie on the positive x and y axes. So, the resultant makes an acute angle with the positive x-axis.

So, R = (5.05 m, 16.93 degrees wrt x-axis)

3 0

2 years ago