1)
first you find the maxium force that the car can produce.
f=ma
Fmax=(1100kg)(6m/s^2)
then use f = ma again to find the accel with the passengers
Fmax=(1100kg +1650kg)(a)
=> a = (1100kg)(6m/s^2)/( 1100kg +1650kg)
= 2.4 m/s^2
Answer:
Explanation:
a )
Amplitude A = 14 mm , angular frequency ω = 2π / T
= 2π / .5
ω = 4π rad /s
φ₀ = initial phase
Putting the given values in the equation
14 = 25 cos(ωt + φ₀ )
14/25 = cosφ₀
φ₀ = 56 degree
x(t) = 25cos(4πt + 56° )
b )
maximum velocity = ω A
= 4π x 25
100 x 3.14 mm /s
= 314 mm /s
At x = 0 ( equilibrium position or middle point , this velocity is achieved. )
maximun acceleration = ω² A
= 16π² x A
= 16 x 3.14² x 25
= 3943.84 mm / s²
3.9 m / s²
It occurs at x = A or at extreme position.
Answer : The distance of the image from the lens is, -42 cm
The height of the image is, 35 cm
Solution :
First we have to calculate the image distance.
Formula used :
where,
f = focal length = 7 cm
p = object distance = 6 cm
q = image distance = ?
Now put all the given values in the above formula, we get the distance of the image from the lens.
Therefore, the distance of the image from the lens is, 42 cm and the negative sign indicates that the image is virtual.
Now we have to calculate the height of the image.
Formula used :
where,
h = height of object = 5 cm
h' = height of image = ?
Now put all the given values in this formula, we get the height of the image.
Therefore, the height of the image is, 35 cm and the negative sign indicates that the image is inverted.
Answer:
glass is optically denser as it is a optical material having more index number above the list