You drop a ball off the roof. It takes 2.5s for the ball to hit the bottom. How fast is it going when it hits the ground?
1 answer:
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Answer:
1. 24375 N/C
2. 2925 V
Explanation:
d = 12 cm = 0.12 m
F = 3.9 x 10^-15 N
q = 1.6 x 10^-19 C
1. The relation between the electric field and the charge is given by
F = q E
So,
E = 24375 N/C
2. The potential difference and the electric field is related by the given relation.
V = E x d
where, V be the potential difference, E be the electric field strength and d be the distance between the electrodes.
By substituting the values, we get
V = 24375 x 0.12 = 2925 Volt
Answer:
The electrical potential energy is 0.027 Joules.
Explanation:
The values from the question are
charge (q) =
Electric Field strength (E) =
Distance from source (d) = 0.030 m
Now the formula for the electrical potential energy (U) is given by
So now insert the values to find the answer
On further solving