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jonny [76]
4 years ago
7

Gary is trying to think of an object that could model a sunspot. His teacher tells him that such an object might be found right

on his face. Which of the following most closely models the behavior of a sunspot? A. an eyelash B. a freckle C. a birthmark D. a lip
Physics
2 answers:
alexgriva [62]4 years ago
7 0

Ans. (B). a freckle.

Sunspots can be defined as temporary phenomena on the photosphere of sun, which appears as spot darker than its surrounding regions. Freckles on the face can model the behavior of sunspots are they represent spots brown spots on skin, darker than face complexion.

Freckles are resulted due to concentrated melaninized cells, having melanin (a type of skin pigment).

Thus, the correct answer is option (B).

const2013 [10]4 years ago
6 0

the answer is B a freckle I just had this as a Study Island and got it right.

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At 9:13AM a car is traveling at 35 miles per hour. Two minutes later, the car istraveling at 85 miles per hour. Prove that are s
andreyandreev [35.5K]

Answer:

There is at least one instant which instantaneous acceleration is equal to average acceleration. a = 1500\,\frac{km}{h^{2}}.

Explanation:

The average acceleration experimented by the car is:

\bar a = \frac{85\,\frac{km}{h} - 35\,\frac{km}{h} }{\frac{2}{60}\,h }

\bar a = 1500\,\frac{km}{h^{2}}

According to the Rolle's Theorem, there is at least one instant t so that instantaneous acceleration equal to average acceleration for the analyzed interval. That is to say:

v'(c) = \frac{v(\frac{2}{60} )-v(0)}{\frac{2}{60}-0}

If car is accelerating at constant rate, instantaneous acceleration coincides with average acceleration for all instant t. Then, instantaneous acceleration is:

a = 1500\,\frac{km}{h^{2}}

6 0
3 years ago
a ball of mass 0.5 kg is released from rest at a height of 30 m. how fast is it going when it hits the ground? acceleration due
Vera_Pavlovna [14]

Answer:

24.25m/s

Explanation:

m = 0.5kg

u ( initial velocity) = 0m/s

v ( final velocity) =?

a = 9.8m/s^2

d (displacement) = 30m

Since u don't have time, u only have the choice to use this formula

V^2 = u^2 + 2ad

V^2 = 0 + 2 x 9.8 x 30

V^2 = 588

V = 24.25 m/s

8 0
3 years ago
How come we can see orange? In simple words.
IgorLugansk [536]

Answer:

<u><em>When sunlight shines through an orange solution, the violet, blue and green wavelengths are absorbed.</em></u> The other colors pass through.

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3 years ago
Calculate the energy released by the electron-capture decay of 5727Co. Consider only the energy of the nuclei (ignore the energy
erma4kov [3.2K]

Answer:

Explanation:

⁵⁷Co₂₇  + e⁻¹  =  ²⁷Fe₂₆

mass defect = 56.936296 + .00055 - 56.935399

= .001447 u

equivalent energy

= 931.5 x .001447 MeV

= 1.3479 MeV .

= 1.35 MeV

energy of gamma ray photons = .14  + .017

= .157 MeV .

Rest of the energy goes to neutrino .

energy going to neutrino .

= 1.35 - .157

= 1.193 MeV.

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Answer: Use less water

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