Constant = 8.314JK⁻¹mol⁻¹
T is for temperature which is 298K
Faraday constant value is 96500C/mol
n is the number of electrons which are transferred in the reaction.
Ecell = E₀cell - RT/nFiN [cathode]/[anode]
Ecell = E₀cell - RT/nF In [PH₂]/[H⁺]²
Ecell = 0.00-8.314 JK⁻¹ mol⁻¹ × 298k/ 2× 96500C/mol In [2.4atm]/ 0.70]²
Ecell = 0.00 - 0.0129 In (2.59)
Ecell = 0.00 - 0.0129 × 0.951
Ecell = -0.0122V
∴Ecell is = -o.0122v
Answer:
Sorry I'm wrong The person above is correct.
I tried.
The statement which is true about a polarized object would be "the number of the positive and negative charges can be the same." Polarized objects became polarized and it has its center of positive charges separated from negative charges.
The kinematic relations allow finding that the answers for the velocity and the position of the car in a time of 2 s. are:
- The velocity is v = 7 m / s
Kinematics studies the movement of bodies giving relationships between the position, velocity and acceleration of the body
They indicate that the initial velocity is v₀ = 1 m/s, that the car has an acceleration of a = 3 m/s² and asks about the position and velocity after a time of t = 2s
Let's used the kinematics relation
v = v₀ + a t
v = 1 + 3 2
v = 7 m / s
We look for the position
x = v₀ t + ½ a t²
x = 1 2 + ½ 3 2²
x = 8m
In conclusion, using the kinematics relations we can find the answers for the speed and the position of the car in a time of 2 S. They are
- The velocity is v = 7 m / s
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