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il63 [147K]
3 years ago
8

A spy in a speed boat is being chased down a river by government officials in a faster craft. Just as the officials’ boat pulls

up next to the spy’s boat, both boats reach the edge of a 4.6 m waterfall. The spy’s speed is 17 m/s and the officials’ speed is 28 m/s. How far apart will the two vessels be when they land below the waterfall? The acceleration of gravity is 9.81 m/s 2 . Answer in units of m.
Physics
1 answer:
babunello [35]3 years ago
7 0

Answer:

They are 7.4m apart.

Explanation:

Here we have a parabolic motion problem. we need the time taken to land so:

Y=Yo+Vo*t+\frac{1}{2}*a*t^2

considerating only the movement on Y axis:

0=4.6-(9.81)*t^2\\t=0.68s

Because we have a contant velocity motion on X axis:

xs=vs*t\\xs=17m/s*(0.68s)\\xs=11.6m

and

xg=vg*t\\xg=28m/s*(0.68s)\\xg=19m

the distance between them is given by:

d=|xg-xs|\\d=7.4m

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The average angular speed of the grindstone is 10 rad/s

\texttt{ }

<h3>Further explanation</h3>

<em>Let's recall </em><em>Angular Speed</em><em> formula as follows:</em>

\boxed{ \omega = \omega_o + \alpha t }

\boxed{ \theta = \omega_o t + \frac{1}{2} \alpha t^2 }

\boxed{ \omega^2 = \omega_o^2 + 2 \alpha \theta }

\boxed{ \theta = \frac{( \omega + \omega_o )}{2} t }

<em>where :</em>

<em>ω = final angular speed ( rad/s )</em>

<em>ω₀ = initial angular speed ( rad/s )</em>

<em>α = angular acceleration ( rad/s² )</em>

<em>t = elapsed time ( s )</em>

<em>θ = angular displacement ( rad )</em>

\texttt{ }

<u>Given:</u>

radius of the grindstone = R = 4.0 m

initial angular speed = ω₀ = 8.0 rad/s

final angular speed = ω = 12 rad/s

elapsed time = t = 4.0 seconds

<u>Asked:</u>

average angular speed = ?

<u>Solution:</u>

<em>Firstly , we will calculate </em><em>angular displacement </em><em>as follows:</em>

\theta = \frac{( \omega + \omega_o )}{2} t

\theta = \frac{ ( 12 + 8.0 ) }{2} \times 4.0

\theta = 10 \times 4.0

\boxed {\theta = 40 \texttt{ rad}}

\texttt{ }

<em>Next , we could calculate the </em><em>average angular speed</em><em> as follows:</em>

\texttt{average angular speed} = \theta \div t

\texttt{average angular speed} = 40 \div 4.0

\boxed{\texttt{average angular speed} = 10 \texttt{ rad/s}}

\texttt{ }

<h3>Learn more</h3>
  • Impacts of Gravity : brainly.com/question/5330244
  • Effect of Earth’s Gravity on Objects : brainly.com/question/8844454
  • The Acceleration Due To Gravity : brainly.com/question/4189441
  • Moment of Inertia : brainly.com/question/13796477
  • The Ratio of the Moments of Inertia : brainly.com/question/2176655

\texttt{ }

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Rotational Dynamics

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